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Overunity Machines Forum



Mathematical Analysis of an Ideal ZED

Started by mondrasek, February 13, 2014, 09:17:30 AM

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0 Members and 9 Guests are viewing this topic.

MarkE

Quote from: webby1 on March 26, 2014, 08:07:43 AM
What a dolt,, Wayne tells me to forget about trying with this group and you make that into what???

Out of the last 80 posts of yours how many were informative and how many were BS posts just like this one?

I think it is YOU who lost credibility a while ago when you started on a rampage of destruction,, forget about anything else destroy at all costs,, that is a really special approach.

Same thing goes for MarkE,, lets not pay attention to the REAL stuff lets just do our best, and even lie about it, to destroy and belittle the "other" people,,

Is gravity conservative?  MarkE says no, I think it is.
There it is again:  I insist that gravity is conservative.  The fraud that you support:  Wayne Travis claims that he can beat the conservative nature of gravity.  By acknowledging the fact that gravity is conservative, you acknowledge that Wayne Travis' claims that you support are false.  Ergo: you directly contradict yourself.  So, why do you support the fraud:  Wayne Travis, Tom?

MarkE

Quote from: mondrasek on March 26, 2014, 08:52:41 AM
"Pre-charge" or "manufacturing cost" or "set-up energy" are Energies that do not leave the system.  If they are present at the initial State 1(x) of the cycle, they must still be present at the final State 1(x) of the cycle.  That is the case with the Ideal ZED being analyzed.  All of the Energy in State 1(x) is still present inside the ZED after it completes a full cycle from State 1(x) to State 2 to State 3 and back to State 1(x).

Please note that there is no return from State 3 to State 2 in that cycle. 

The "pre-charge" in your example is misnamed.  It is actually just a "charge."  It is analogous to the Energy used to charge the Ideal ZED from State 1(x) to State 2.
PirateBill's comical LED ZED is more useful than either an "ideal ZED" or a "real ZED".  His logic is every bit as valid as the fraud Wayne Travis'.  And of course he's just running down his potential energy store.  Even the "ideal ZED" does that.

So, what was the point of your recent example with the 44mm water pan?  As that only extracts 49.9uJ out the 1905uJ energy that you have to put back in to get from State 3 back to State 2 it sets up a 97%+ State 2 <=> State 3 cyclical loss.  PirateBill's LED ZED can be made much more efficient than that.

MarkE

Quote from: webby1 on March 26, 2014, 09:56:37 AM
Alrighty MarkE, I will bite on this one :)

How much energy can a resistor dissipate at room temperature.

It is my understanding that it can not dissipate any and that is what leads to the resistance of the resistor going up.
Clearly again, you do not understand.  There is an entire class of resistors used in many applications where the resistance goes down as they heat up.  They are called negative temperature coefficient thermistors.

mondrasek

Quote from: MarkE on March 26, 2014, 12:15:42 PM
So, what was the point of your recent example with the 44mm water pan?  As that only extracts 49.9uJ out the 1905uJ energy that you have to put back in to get from State 3 back to State 2 it sets up a 97%+ State 2 <=> State 3 cyclical loss.  PirateBill's LED ZED can be made much more efficient than that.

I was interested if you would point out that it was not a correct method for trying to calculate the Energy that leaves the ZED system when it lifts from State 2 to State 3.

Why do you keep bringing up anything about the Energy it takes to go from State 3 back to State 2?  That never needs to happen.  The full cycle can be:  State 1(x) to State 2 to State 3 to State 1(x).

MarkE

Quote from: mondrasek on March 26, 2014, 12:36:52 PM
I was interested if you would point out that it was not a correct method for trying to calculate the Energy that leaves the ZED system when it lifts from State 2 to State 3.

Why do you keep bringing up anything about the Energy it takes to go from State 3 back to State 2?  That never needs to happen.  The full cycle can be:  State 1(x) to State 2 to State 3 to State 1(x).
Given that you have described the steps of putting water into the machine as set-up, that left states 2 and 3 for a cycle.  But if you want to cycle among other states, that's fine too.  If you don't come up with some sort of harvesting mechanism to collect energy that you dump from the stored water by returning to any state lower than State 2, then you will massively aggravate the cyclical losses.  If you do come up with a harvesting mechanism, depending on how efficient it is, and it will always be less than 100% efficient, it will simply increase the cyclical losses versus cycling only between State 2 and State 3 with your pizza pan of water spillway contraption. 

As to method of calculating energy, you did not show one.