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Overunity Machines Forum



Akula0083 30 Watt Self Running Generator.

Started by Grumage, March 06, 2014, 12:29:06 PM

Previous topic - Next topic

0 Members and 11 Guests are viewing this topic.

T-1000

Quote from: verpies on March 31, 2014, 06:05:49 AM
Indeed, the usual electronic operational principles prevent the Akula's circuit and transformer from exceeding unity O/I power ratio, unless something unconventional happens in that transformer. 
The conventional behavior of the transformer in this circuit is pretty accurately illustrated by the simulations posted in this thread.

As I said in beginning, the trick is in transformer... :D
And what effect needs to be there to trigger COP >1 condition - still not very clear.
Perhaps Grum had it very close with adding noise to circuit and having transformer fully ringing between each sharp pulse?

Cheers!

avalon


Grumage

Quote from: avalon on March 31, 2014, 04:24:43 PM
Oh, for Pete's sake!

Dear Avalon.

Welcome to the thread, Oh and by the way I'm Grum, not Pete !!  :)

Sorry your Sim looks good but it does not show very clearly the 2 to 3 second dying oscillations that I am seeing after power off !! Just need some more noise !!  :)

Cheers Grum.

MileHigh

Wattsup:

I have a real treat for you:  https://www.youtube.com/watch?v=IsD7DlKBu0g

QuoteHmmmmmm. I would have thought the contrary as at resonance usually amp draw goes down and voltage goes up.

Amp draw goes down once the resonator is filled with energy.  But that's a temporary "overdraw" condition.  The problem is that maximum voltage equals maximum current when the voltage is zero.  That's where the losses are, in the resistance of the wires.  So resonance is a power draw.  The amplitude of the resonance gets as high as it can which is determined by how much power can be supplied by the source.  For example, if someone can get a transformer to resonate, they can measure the power draw of the transformer at the resonant frequency, and just below or above the resonant frequency and compare.  The point is to not take anything for granted.  I have never done this, so I am not telling you this will exactly happen, but the measurements should be made.

I am not convinced that you will be able to make the transformer resonate in the circuit.  However, chances are you could if you drove the isolated transformer with a swept sine wave from a signal generator.

MileHigh

P.S.:  Lesser known and perhaps a good jam song:  https://www.youtube.com/watch?v=vBXk5A-TpwY

Farmhand

Quote from: MileHigh on March 31, 2014, 07:12:14 PM
Wattsup:

Amp draw goes down once the resonator is filled with energy.  But that's a temporary "overdraw" condition.  The problem is that maximum voltage equals maximum current when the voltage is zero.  That's where the losses are, in the resistance of the wires.  So resonance is a power draw.  The amplitude of the resonance gets as high as it can which is determined by how much power can be supplied by the source.  For example, if someone can get a transformer to resonate, they can measure the power draw of the transformer at the resonant frequency, and just below or above the resonant frequency and compare.  The point is to not take anything for granted.  I have never done this, so I am not telling you this will exactly happen, but the measurements should be made.

I am not convinced that you will be able to make the transformer resonate in the circuit.  However, chances are you could if you drove the isolated transformer with a swept sine wave from a signal generator.

MileHigh

The power draw at resonance depends on a few factors, "Q" factor of the coil is one factor and also the level of voltage used and achieved as well as the capacitor resistance and frequency.

My small Tesla coil primary with feedback oscillator has 1 mm wire and I can get a fair bit of activity in it with only 300 mA input, very much more watts than the few watts input, it gets up to like 200 Watts or so activity but the input at resonance is more than when not, when not at resonance the input is almost nil.

That's why I built my bigger Tesla coil with 1 mm wire in the secondary, how many Tesla coils you see made with 1 mm wire secondary ? I worked out a rough "Q" of 6000 or so for it. 3.2 Ohms resistance or is it only 1.6 Ohms resistance I can't remember, 4 mH and 760 kHz. I think it has a bit more than 4 mH inductance, been a while since I measured it.If the resistance is only 1.6 Ohms then the "Q" would be closer to 12000. Which would be good.  :) EDIT I just worked it out by wire length and resistance for the wire per klm and it is more like less than 2 Ohms, so I'm gonna say the "Q" is more like 9000 for the bigger Tesla coil.

Circuit Sage "Q" factor calculator.
http://www.circuitsage.com/tools/tool_view&tool_id=17

I would say if people want to resonate coils the coils should be high "Q", this seems to be ignored. Resonance can change the impedance of a coil but it cannot change the DC resistance, the DC resistance will always burn up power. The oscillating losses can be calculated by the DC resistance and the oscillating current ect.

It makes no sense to me to resonate a coil with a lot of DC resistance, it will get hot and the heat will be produced from the input supply's energy.

Cheers

P.S. Of course the exception is if resonance is wanted to increase the voltage output of a transformer ect. and the power dissipated is not a concern.

If we have a coil which has 140 Ohms resistance it burns enough power making the current flow through it once not to mention non stop oscillating current.

If a coil is going to act as a high resistance to reduce input it makes no sense to have it resonate.

The near infinite resistance of parallel resonance can reduce input in some situations. It depends on stuff.

..