Quantum Energy Generator (QEG) Open Sourced (by HopeGirl)

[pmgr]

Thanks Mark for reminding me about the core losses, it completely slipped my mind.

I don't think that there has been that much discussion about magnetic hysteresis loops and eddy current losses on the Be-Do forum. MileHigh

@MH et al

I am planning on addressing the core losses and hysteresis losses in my model.

I have done some research online, but would like to get input from people who are familiar with these terms.

For M19 steel, I have found the following numbers:

For 0.014" laminations (29 gauge), core loss at 15kG (1.5T) is 1.55 Watts/lb.

I couldn't find any numbers for the hysteresis loss for M19 steel, but did find it for M15 steel and it is 0.0068 Joule/(lb*cycle) at 10kG (1T).

Now here are my notes and questions:

1. Total core loss can be calculated by multiplying 1.55 Watts with the weight of the core/stator.

2. The unit of hysteresis loss is Joule/(lb*cycle), which is equivalent to Watts*sec/(lb*cycle) = Watts/(lb*cycle/sec)

Assuming the rotor turns at 2400rpm (f=40 RPS) and thus inductance modulation at 4*f cycles per sec, hysteresis losses would be 0.0068*4*f times weight of the rotor/stator (losses in Watts).

Not sure how heavy the QEG is, but let's say it is 80lbs.  Then we get the following:

1. Rotor/stator losses are 1.55*80 = 124 Watts
2. Hysteresis losses are 0.0068*4*40*80 = 87 Watts
3. Resistive heating losses in primary coils are I*I*Rcoils equal approximately  1*1*36 = 36 Watts assuming a 1 Amp (rms) tank current.

So total steel losses are then about 211 Watts. Heat loss of 36 Watts for a total of 247 Watts.

Now, here is where I need your feedback. How can I implement the core and steel losses into my model?

Can I simply model them as an additional resistance in the primary tank circuit in series with the coil resistance? In this particular case that would translate to changing the coil resistance from 36 ohms to 247 ohms? Of course assuming the tank current remains at 1A rms.

Or should this be modeled as an external load, e.g. in parallel with the capacitor? Or maybe it can be appropriately modeled either way?

PmgR
================================================
Help stop the persecution of Falun Dafa in China!
Stop organ harvesting from living people in China's labor camps
http://www.faluninfo.net
================================================
Falun Dafa, also known as Falun Gong, is an ancient Chinese
self-cultivation practice, based on the principles of
* Truthfulness * Compassion * Tolerance *
Great for improvement of health and mental well-being!
http://www.falundafa.org
================================================

[MileHigh]

Pmgr:

I am not a modeling expert.  But my sense is that putting small resistances in parallel across tank circuits could suffice.

Also, we know that hysteresis losses should increase as frequency increases.  I don't see that in the formulas so I am somewhat confused.  I noticed they are using interesting "rationalized industrial" units which is pretty cool.

I have a feeling that core losses are probably not linear with respect to things like AC Tesla strength and probably frequency.  So my suggestion would be to do some experiments around a fixed operating frequency.

Perhaps there are transformer and choke models in pSpice that factor in core losses?  It's pretty much uncharted territory for me, I did like three or four Spice simulations in my life and that was back in the Eighties!

I also note that the wattages you are estimating sound like you are on the right track.  It all harks back to my thermal profiling experiment that probably nobody will ever do!

Poor Team FTW.  If various analyses converge on a unified description of the operation of the QEG, you will be left with a naked QEG with no secrets!  Where is a supercomputer when you need one?  It's in your graphics card!

MileHigh

[isim]

@TinselKoala
Your implémentation is on the left of my attachement.
May i suggest you to use the rigth implementation, if your generator as floating output!

So the Probe of the MainCoil does not see the voltage of the resistor.
@+

[isim]

@TinselKoala
Here is the sim with your new info:
R=3 ohms Lmain_coil=160n Vgenerator=68pp
Calculed Power generator=185.92W
Power generator=Power MainCoil + Power Resistor
                         =1.8172W-184.1W=185.9172W ~ 185.92W
(forget about minus sign in Power average, it come from I(V1), It must be I(R1))

Do you want the same sim with R=0.25ohm  ?
@+

[MileHigh]

Here is an alternate view of UK has Resonance!!  If it was in black and white, it would look like an old Twilight Zone episode.

https://www.youtube.com/watch?v=IrdOmNDpUss

The comments are pretty funny and apparently unmoderated.