Quantum Energy Generator (QEG) Open Sourced (by HopeGirl)

[Farmhand]

Here's a shot I took this morning, the purple trace is (X times Y) Math, but I have no idea how to interpret that to an actual
power value (scope doesn't do it). I need to connect to the computer and really get a grip on the UltraScope program, maybe
that will help.

Anyway. What does MATH Scale - 50.0 Vz mean ? User guide doesn't say what it means or anything about MATH except FFT.

I'm not sure but I think I should be inverting the current sense (blue) trace because it's common ground, but I'm not sure
it matters in a tank, I'll play more later.

First shot is the HV tank. Second shot is the Output tank with no load.

..

[Farmhand]

AHAH, I thought the measurement for current was too hig, so I took the measurements again and it seems I had an issue with the
blue probe. It seems the current is much less, only 1.8 amps. I also inverted the blue trace for the current.
.

[TinselKoala]

@Farmhand:
The Math trace is showing you "V²" not "Vz". Since you are multiplying two voltage traces! It probably does that instead of "VV" like some scopes do, for reasons that should be clear: VV looks a lot like W.

But that's kind of encouraging. Perhaps the channel you are using for "current" has, in the "probe type" menu, an option for "Current Probe" and some choices under that. If you choose one of these, the Channel display should then read out in Amps and the Math trace will give you W instead of V² .  At least many DSOs with math operate that way.


So to get from your "Vz" or really V x V trace to power, you have to know the value of the CSR to scale the reading. The reading on the scope will be (50 / Rcsr) Watts per division since the second V is really I = Vdrop/Rcsr. At least if I did the algebra right.... please check.

[Farmhand]

Thanks a heap Tinsel, I owe you a cheeseburger. 

The CSR is 0.1 Ohms. So that would be 500 Watts per division ? Maybe I should make some carbon block resistors at 0.1 Ohm.

I'll check out the probe options and try connecting to the computer later for a closer look.

P.S. Well that doesn't make a lot of sense either when I do the power calculation.

340 RMS x 1.82 RMS = 618 VA
618 x 0.73 = 451 W
618 - 451 = 167 VAR

Must be the phase angle measured is incorrect. The probes have capacitance that I just tune with (use it to tune) it has an effect
as the total capacitance for the HV tank is only about 1 nF. And the resistor is a wire one.

.

.

[Farmhand]

Tinsel could you please check the current magnitude with the reactance method ? The coil is 320 uH. Frequency is 294 kHz and
the voltage is 340 VRMS. I'm concerned the electric field is influencing the probe.

Or better still can you just give me the formula, some tips, and I'll give it a go.

..