Quantum Energy Generator (QEG) Open Sourced (by HopeGirl)

[Farmhand]

Here's another way to look at the load circuit configuration. No one mention Mr D Smith pleeeaasse !
Basically the tube can be a very lossy transmission medium, another load could be connected between
the fluorescent tube and the ground using the ground as a return. SWER. So the fluro current can be
measured that way as well, if one had the correct equipment.

@ all reactive power OU claimants.

1) The tank is the source of AC power, but the battery supplies the energy.
2) This is where the reactive power OU claimants fall very short !
3) They need to understand that power is not energy and a generator only makes power not energy.
4) The battery supplies the energy which is stored potential energy in some form depending on the battery,
or potential source.
5) The AC generator dissipates energy just to make the AC power available.
6) The energy is transferred from the source of stored potential.
7) The tank is a "tank" as in a storage tank.
.

The power generating facility cannot turn reactive power back into coal then reverse the energy it took to dig the coal up
and burn it to make the heat to generate the power so the reactive device can reverse it.

That's the problem with reactive power.

[Farmhand]

This circuit should be able to do something to see if the "currents" before full conduction and/or if the reactive portion
of the tube power can be rectified and consumed. If I test with a small motor when the tube activity seems highest
before full conduction and during full conduction then I should see some result.

Second Schematic-

Similarly I could put a small capacitor in series with the tube and that should shift the phase of the currents.
Shouldn't it ? And improve the "real" power factor.
EDIT: DoH ! the load sense resistor should be below the PFC capacitor. 
.

[isim]

The 0.1 Ohms resistor is in series with the load "outside the tank" The load waveforms are a lot different to the tank wave forms.
....

Yes, you got it. As the Voltage and Current are sinusoidal, we can use the formula:
Pload=Vload Rms*Vcsr_rms/CSR=84.8 * 0.0922 * cos (12°)=7,65 W
This same very resonable!
And I think it is...
Look at the power curve, no symetry, the GND is near the peak value of the curve! the CF is cos(12°) = 0.978 ~ 1
Just for the fun, can you send me the CSV file of this mesureament?
I would like to compare it with the simulation.
Here a link on a direct drive of fluorescent lamp:
http://www.ee.bgu.ac.il/~pel/pdf-files/conf79.pdf

PS: I don't think it's a good idea to take a bigger CSR, It value must be very low compared with the others impedances. Otherwise you change the functioning point.

Thanks
@+

Edit: I made an error!
I forget the CSR, so with CSR=0.1ohm

Pcsr=I²*R=(Vcsr_rms/CSR)²*CSR=Vcsr_rms²/CSR=(0.0922)²/0.1=0.001W, it's nothing.
and
Pload=Vload Rms*Vcsr_rms/CSR=84.8 * 0.0922 * cos (12°) / 0.1 = 76.5 W
with your last measurement file (csv) I got 76.58W.
Is it compatible with your Lamp?

[Farmhand]

No, Thank you Isim. You are very kind.  I appreciate all the help I can get.

I personally think everything will add up real nice and neat once we take everything into consideration. Hopefully we can do that.

I will get the CSV. But I'll have to do the measurement again, the traces should be very similar. Ta.

For "Real and proper measurements" I would also need to take into account all the ground currents pre existing with a resonant
relationship to my working frequency if the output coils are connected to ground, as well as AC displacement from the grid influence and all kinds if stuff, I imagine. ie. my working frequency is exactly half the radio station frequency. Not that I believe
much power can come from that to this arrangement.  Not without a massive capacitive antenna and good Earth ground.
hahaha. on the other secondary of course as a receiver. Power Adder, rofl.  Is that a serpent ?
.

[isim]

Erreur, I cancel it.