Quantum Energy Generator (QEG) Open Sourced (by HopeGirl)

[Void]

Well when I get an appropriate CSR and ensure no ground loops then if I get this shot below I can claim OU ?
That's 3.8 Watts input and 5.1 Watts out.  If we use the scope measurements and calculate.
When I get the proper CSR we or I will determine the phase to verify with the scope display.

Don't ask me to explain where the extra energy comes from if it does still show more real power out than in.   
I'll let you do that if you want.
..
Input 12.4 V x 0.3 A = 3.72 Watts
I figure it like this.
(200 cosine = -0.987 PF)
84.6 volts x 0.987 A = 83.5 VA
83.5 VA x 0.987 = 78.4 VAR
83.5 VA - 78.4 VAR = 5.1 Watts
5.1 Watts output / 3.72 Watts input = 1.37 C.O.P
..
I think I did better with the filament light bulb and the previous setup not sure.
.

No idea what you are trying to do here.
The scope shot you attached to your post says 'tank traces', but
if that is the secondary tank circuit it has no bearing on the efficiency
of your circuit. You only need to show the voltage waveform across the load
and the current waveform on a CSR connected to one of the load terminals.
Watch out for scope ground loops if you have two scope probes connected
into different points in the circuit at the same time. This can also throw off
your measurements, but I think you showed that you have both scope probes
grounded at the same point.

[Farmhand]

Void my friend, I got similar results with a filament globe. a 3 Watt incandescent filament light globe, just like most others use and
call resistive loads. But this is 420 kHz. Less dangerous at the same voltages than 50 Hz. It will not kill me unless without any large
capacitors in the arrangement. Makes it more like fun than a chore.
.

[Farmhand]

No idea what you are trying to do here.
The scope shot you attached to your post says 'tank traces', but
if that is the secondary tank circuit it has no bearing on the efficiency
of your circuit. You only need to show the voltage waveform across the load
and the current waveform on a CSR connected to one of the load terminals.
Watch out for scope ground loops if you have two scope probes connected
into different points in the circuit at the same time. This can also throw off
your measurements, but I think you showed that you have both scope probes
grounded at the same point.

The difference between VAR and VA is real power in watts, isn't it ?. Doesn't matter where it goes if it's shown to be more
than the input, what matters is where it comes from.
If it is shown to be accurate, then it's anomalous heat or something, but it isn't accurate is it, neither is the load power.

I want to measure the power consumed by the fluro as well as other loads and show the effect on the generator of AC
and the reactive and active powers ect.

P.S. At the moment it's cold here so I can count all the heat output as useful output. If I want to.  I have no master. When it's
cold I can consider what is usually waste heat to be useful because it is, it adds heat to my hut.
.

[Void]

Void my friend, I got similar results with a filament globe. a 3 Watt incandescent filament light globe, just like most others use and
call resistive loads. But this is 420 kHz. Less dangerous at the same voltages than 50 Hz. It will not kill me unless without any large
capacitors in the arrangement. Makes it more like fun than a chore.
.

Ok, I looked at your last scope probe placement diagram you posted a while back, and I think I
understand how you are measuring the load current and load voltage waveforms. The scope probe placement looks correct.
I don't know how to explain it either. I need to think about it. I have also seen strange phase shifts like this before, and I
have seen in some such cases that a small change in frequency can completely change the measured results. If you change the frequency of the driver
somewhat does the measured phase shift on the load current change quickly? 

[Void]

The difference between VAR and VA is real power in watts, isn't it ?. Doesn't matter where it goes if it's shown to be more
than the input, what matters is where it comes from.
If it is shown to be accurate, then it's anomalous heat or something, but it isn't accurate is it, neither is the load power.

I want to measure the power consumed by the fluro as well as other loads and show the effect on the generator of AC
and the reactive and active powers ect.

..

Once you multiply  Vrms by Irms by the PF for your load, you get Watts. That is the real power P (AKA True Power),
and real power is expressed in Watts.
VA is used to represent the apparent power, signified as S. This would be your measured Vrms times your measured Irms for your load.
VAR is used to represent the reactive power, signified as Q
Apparent power is the vector sum of the reactive and real power.