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The Bessler Wheel, mystery solved.

Started by gurangax, April 24, 2014, 02:40:13 PM

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0 Members and 7 Guests are viewing this topic.

gurangax

Quote from: gurangax on April 25, 2014, 10:19:40 PM



You need to program the computer to do something. and since i can say that every perpetual motionist thinks about the same failures then how can someone programs it the right way. There is something common that why they failed. But that is for later talk. anyway I have already put some clues to it and still many doesnt get it. I wonder why.


send me a simulation program and I will show you how it is done. regards

gurangax

The z axis is the key!


regards.


ps: I need to fix my broken cylinder head today so I wont be available until im finished with it. anyway keep posting bad or good. doesnt matter to me.

vineet_kiran

Quote from: gurangax on April 25, 2014, 05:33:07 AM

Bessler was trying to hint the mechanism used in his toy drawings MT138. It's not easily seen but when put properly you will get the 2 stage leverage.

For those who doesnt know what is MT138 please go to this link http://www.besslerwheel.com/wiki/index.php?title=MT_121-143#MT_138-141



In that figure if the standing toy hammers the lever it beomes external force (impulse).  Only then the lever can move in the indicated direction.   If the toy only pushes the lever then it becomes internal force and lever will not move in the indicated direction because the reaction at the bottom of the toy pushes the lever in opposite direction.

Without an external force you cannot build even a underunity device.  In a system of levers, only impulse can create an external force. 

A best example would be,  if you sit inside a car and push the car, the car will not move forward because your back will be pushing the car in opposite direction. Only if you get down car and push it, then the car moves forward.

Where is the external force in the figures shown?  Can you please clarify?


gurangax

Quote from: vineet_kiran on April 25, 2014, 10:37:08 PM


In that figure if the standing toy hammers the lever it beomes external force (impulse).  Only then the lever can move in the indicated direction.   If the toy only pushes the lever then it becomes internal force and lever will not move in the indicated direction because the reaction at the bottom of the toy pushes the lever in opposite direction.

Without an external force you cannot build even a underunity device.  In a system of levers, only impulse can create an external force. 

A best example would be,  if you sit inside a car and push the car, the car will not move forward because your back will be pushing the car in opposite direction. Only if you get down car and push it, then the car moves forward.

Where is the external force in the figures shown?  Can you please clarify?




NO impulse is used. forget about impulse. if you push the car from the inside surely the car wont move, but if you turn the gearbox from the inside then surely the car will move. OK. back to work,


regards

vineet_kiran

Quote from: gurangax on April 25, 2014, 11:06:26 PM

... if you push the car from the inside surely the car wont move, but if you turn the gearbox from the inside then surely the car will move. OK. back to work,

regards


Can you turn the gear box flying in air?   You have to stand or sit firmly inside the car to turn the gear box. Where that force will act? 

To perform mechanical work in one direction, you should have equal force in opposite direction which follows directly from Newton's third law.  In a single system, these two forces cancel off and you will not get any useful work.