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Need MEG circuit help

Started by magnetman12003, July 23, 2014, 07:23:46 PM

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magnetman12003

Hi,

Below is a small hand drawn diagram of what I hope to be a MEG circuit that works.
I already have a split core transformer and would like input as to the way D1and D2  diodes should be marked as well as capacitors C1 and 2 polarities.

I am not sure if the INPUT coil side should be wound clockwise or counterclockwise.  The same goes for the OUPUT side of the transformer.

In any event I wish the current to flow from the input side of the transformer to the output side. ONE WAY.

I have an idea I wish to try that may make this work.

It may not work at all but with your help at least I will know that the current will be flowing in one direction as shown

Here is the diagram:

http://web.mail.comcast.net/service/home/~/?auth=co&loc=en_US&id=1015181&part=2

vasik041

I can't see diagram.
Probably it is good idea to attach picture to your post.

Bob Smith

There are some technical papers and suggestions from user, "Smudge" on building the MEG at this link:
http://www.overunity.com/14614/the-bearden-meg/
Bob

magnetman12003

Quote from: Bob Smith on July 24, 2014, 07:31:49 PM
There are some technical papers and suggestions from user, "Smudge" on building the MEG at this link:
http://www.overunity.com/14614/the-bearden-meg/
Bob
Thanks for the info  I found everything I need by looking at the papers.  I saw how both coils are wound.  Also noted the direction of current flow in which I will place diodes with correct polarity.
The caps are not electrolytic so no problem there.     

As I see it the INPUT side of a over unity transformer when first PULSED with an external DC source causes a voltage spike to be generated in its coil.  That spike is transferred to the OUTPUT side of the transformer where its iron core "MUST" have more  permanent magnet assistance than the INPUT core does.
Hence a larger spike will be generated by the OUTPUT. Then that spike is transferred back into the INPUT once more.  Diodes and small caps keep the voltage/current flowing only in one direction.
Since we have a closed  loop situation the process goes on resulting in a buildup of hi unknown AC voltage/ current continuously flowing inside the loop.        How does all the above sound coming from a laymen?

MarkE

It describes the concept perfectly.  Unfortunately, reality ignores the concept.