Partnered Output Coils - Free Energy

[TinselKoala]

My answer is 100 percent correct. Bill's answer is slightly off, since my calculator uses integer math which is conservative.


Maybe EMJ means to represent the total E field from both bucking coils as "E". Then E/2 would be the contribution of one of the coils, that is, one half of E.
The electric field is a vector, its units are volts/meter and in vector calculus it is the negative gradient of the voltage (scalar) at the measurement point.

[EMJunkie]

Maybe EMJ means to represent the total E field from both bucking coils as "E". Then E/2 would be the contribution of one of the coils, that is, one half of E.
The electric field is a vector, its units are volts/meter and in vector calculus it is the negative gradient of the voltage (scalar) at the measurement point.

OK, I like this answer!

TK, you impressed me here! Will wait and see if we get any better. Currently this answer is the best.

  Chris

[Pirate88179]

My answer is 100 percent correct. Bill's answer is slightly off, since my calculator uses integer math which is conservative.


Maybe EMJ means to represent the total E field from both bucking coils as "E". Then E/2 would be the contribution of one of the coils, that is, one half of E.
The electric field is a vector, its units are volts/meter and in vector calculus it is the negative gradient of the voltage (scalar) at the measurement point.

My answer is only slightly off?  That is closer than I usually get. (Grin)

Bill

[TinselKoala]

I had to rewind the primary to get rid of the shorting from L1-L2, so now of course it's shorting inside the L3 coil. Makes nice ozone, still lights 30 neons in series but also still is unstable at high voltage outputs. Running it in the "EMJ" mode with underdriven transistor is a piece of cake, no problems there. I've put in 3 series neons on the HV output to keep the spikes from getting to the insulation-breakdown point until I can rewind the coils with proper HV precautions and better wire.

For square wave (approx. 56%HI-44%LOW duty cycle) at 1745 Hz the 555 timer circuit suggested by Slider works a treat and has plenty of "oomph" to drive the bipolar transistor into full turnon and great HV output. Power the 555 in parallel with the power to the main circuit. Use a 200R or 500R trimpot as a "volume control" to bring the drive down to the "underdriven" state that is shown in EMJ's scopeshot. This reduces the HV spike to 400V with the 10R load connected and 1kV with the load circuit open.

I still think that the mosfet works better though. It makes the HV spikes just fine and takes _much less_ drive signal. The increased drive current required by the bipolar transistor adds to the total input power of the system and doesn't do anything except go to ground as it is making the transistor conduct. The mosfet's gate just needs to be filled with charge and leaks very little power to the other terminals of the mosfet so it works with much less drive signal from FG or from the 555 oscillator.

[prochiro]

E stands for the product of one set and 2 stands for geometrical additions as in other pairs to multiply results as in combinations working together not to double but a multiple of the same.
Prochiro