Partnered Output Coils - Free Energy

[EMJunkie]

I also found a Picture of your Local Servo Bill!

Is this where you fill Up?

It looks like a very Pleasant Colony!!!

   Chris Sykes
       hyiq.org

[forest]

EMJunkie


I thought maybe cifta would respond. I cannot measure or catch the difference because of analog scope lack of feature of storing waveform.
It's just that : you take a resistor and charge capacitor from DC power source - nice clean understandable waveform.
Now, you do the same with inductor having the same resistance , from the same source - what is REALLY happening in the first few microseconds ? does inductor resist current flow due to inductance ? I suppose ,yes , but I can't see it.

[citfta]

Hi Forest,

Sorry for the slow response.  I have been kind of busy lately and forgot about your first post.  I have not tried to discharge one inductor into another inductor but I think I have a pretty good idea what would happen.  As you posted an inductor does resist the change in current flow.  It resists both an increase in current and a decrease in current.  A simple explanation for how an inductor works is to think of it this way.  You know that a wire carrying a current has a magnetic field around the wire.  Now if we coil that wire up on a spool or other form we now have each turn of the wire next to another turn of wire.  So as the current starts to flow each turn of wire has a magnetic field that is acting upon the turns next to it.  The action is to produce a voltage in the other turn that opposes the applied voltage.  This action limits how fast the current can rise in an inductor.  Once the current in the coil reaches the point where it can no longer increase because of the dc resistance of the coil then the inductance effect stops and the magnetic field stabilizes.

Now if we turn off the voltage going to the coil then the magnetic field starts to collapse.  As the magnetic field starts to collapse it induces a voltage on the turns of wire that try to keep the current flowing in the same direction as it was before the voltage was turned off.  If there is no load for that current to go to then it will try to arc across the switch contacts or go through the transistor or whatever device was used to turn the voltage on and off.

I think your original question was what happens if you discharge one inductor into another inductor?  That all depends on the inductance of the two inductors.  I think you said they were of equal value.  In that case you should get a discharge curve very similar to the charge curve.  If the second inductor had a much lower inductance than the first then you would get a slower discharge curve.  That really seems backwards doesn't it?  Well you have to remember there is only so much stored energy in the coil.  A rather weird thing about coils is how they discharge that energy.  If we have a high resistance or inductance for it to discharge into, the coil will generate a high voltage to overcome that resistance or inductance.  A higher voltage means a loss of current so the pulse will be very short.

Now if we discharge the coil into a low resistance or inductance the voltage generated will be low and the current will be high so we get a longer discharge time.  This is because the higher current helps to maintain the magnetic field.  Remember that an inductor wants to keep the current flowing at the same rate and adjusts to try and do that.

I have included a link to a video about inductors and there are plenty more to watch and learn from.  I did not find one that shows a discharge from one inductor into another although what gotoluc and some of the others on this forum are doing is probably pretty close to what you are interested in.

https://www.youtube.com/watch?v=NgwXkUt3XxQ

Keep studying and you will learn a lot more than you can imagine.

Carroll

[MileHigh]

Suppose you have two equal sized inductors and they are not magnetically coupled.   If the first inductor has one amp flowing through it and the second inductor has zero amps flowing through it, when you discharge the first inductor into the second inductor the current flow will nearly instantly take a step down to one-half amp.  For a very short time when the connection is first made, the first inductor will generate a very high voltage spike and then it will nearly instantly disappear and then one-half amp will be flowing through both coils.

[forest]

Ok, I was too inaccurate. If we have a coil of thick wire, thus having low inductance and low resistance and charge capacitor from battery via this coil , can you catch the difference in charging waveform to the non-inductive resistor of the same resistance.


Second question is more important and I know there was a long discussion about it.
When you connect coil to the battery and disconnect and connect to the capacitor just at the moment when the core saturates then it become a pure resistor to the power source so it should be large current charging capacitor and also EMF from magnetic field collapse. Is that collapse producing additional current at higher voltage then power source or rather it is acting purely on the current from power source flowing through the resistance of the coil turns.
Two currents or one current ?