Partnered Output Coils - Free Energy

[MileHigh]

In looking at it some more, I am still seeing it my way.   Look at the channel 2 current waveform.  When the current is flowing, that is the coasting phase where the loop driven by L1 is circulating and the MOSFET is OFF.  So that is section A, I assume we agree on that.

The pulse frequency is quite high, and as a result you can see the by the current waveform that perhaps a bit less than one time constant has transpired before the MOSFET switches on at the beginning of point B.  Since L1 still has current flowing through it, and we see that L1's current can either go through D1 or the MOSFET.  The current from L1 through D1 is extinguished by the end of phase B and L1 is still charging up again but we can't see it with the current probe because the current probe is in the main loop.  At the end of phase B the diode stops conducting.  It's like a switch opening and the loop is dead.  Since the loop is dead the source for the potential reference now comes from somewhere else, the 6.7 volt supply.

From point C to point E, the current in the loop is dead.  Because there is no current in the loop and D1 is not conducting, the channel 1 voltage sense is coming from the +6.7 volt source.  (It look more like about 10 volts on the scope trace.)

So you are looking at an approximately 50% duty cycle waveform from the function generator to the MOSFET gate.

Also, I just realized that whatever the actual mechanism for the big oscillation at point E, you can see what the ultimate result of it is - the current gets flowing in the main loop again.  So it's like L1 hits the loop like a sledge hammer the moment the MOSFET switches off, and there is a lot of nasty vibration, but eventually the resonating box you hit with your sledge hammer gets moving.  So the ring-down is the vibratory resistance to the impulse of energy from L1, but eventually L1 wins and starts to get current flowing in the loop again.

I am sticking to it!  lol

[Vortex1]

As we don't know exactly where the scope probes are connected it is difficult to comment on the waveforms, however at first glance I also thought the FET switch off was at "E", but the ringing is way too high for a diode clamped circuit.

To me, the very short, very high burst at "E" is reminiscent of stored energy in the diode capacitance, A drift step recovery effect or it could be just a parasitic oscillation of the FET / L1 / diode capacitance.

For now and for lack of more info regarding probe placement, I will (LOL) stand by point "B" as the FET turn on and point "C" ringing as normal diode clamped ringing, considering that since the "bucking coils" are in series with the diode, they allow for imperfect clamping and enough ringing to initiate the DSR effect.

I believe Verpies first posted the attached graph for a different DSR circuit. such a DSR spike could certainly excite any stray inductance and borderline parasitic tendency.

There is also the remote possibility of an induced NMR effect due to the orthogonal field of the bucking coils superimposed on the normal field of the ferrite...very remote.

MH we can agree to disagree....no harm...all in the spirit of getting to truth.....you may be right!

[MileHigh]

Ion, I agree that the real way would be to have more information.  I respect your extensive experience here also which I don't have at all.  It's fun in a way to do this but on the other hand I hate doing it because of the uncertainty.  However, we all can agree that the power-out measurement is not valid.

MileHigh

[picowatt]

MH,

Keep in mind that area A is roughly at the supply voltage (actually a bit closer to 6V).  The peak voltage seen just after Q1 turn on (excluding the ringing) is is roughly 10-11 volts.

When Q1 turns on, current flows thru the primary.  The turns ratio of L1 to L3 increases the voltage at the R1/L2 junction above the rail voltage (the voltage induced across L3 adds to the rail voltage).  D1 is reverse biased so L2 can only play via cap coupling and leakage (i.e., very little).  Also, because D1 is reversed bias, little to no current can flow thru R1 as indicated by the current probe during this time.

Having spent only a short time looking at it, that's my take on it so far. 

PW

[EMJunkie]

@ALL

I suggest you spend 10 minutes and build the device and test it for yourselves! Most all here will have the materials laying around!

This would save the speculation and talk about things I haven't done when in-fact I actually have!

You just may Learn something!