Partnered Output Coils - Free Energy

[Pirate88179]

Bill, MileHigh,

Apparently, Kim Jong-Un is building Free Energy Devices, same as mine.

Apparently they are going to be used to power his own country, then he's going to turn you all into Rats and run you all ragged on little Wheels to turn your Generators to power your Homes!

Hahaha - you Total Defuses!!!

OK, I am guessing that this is yet another False Claim.  If not, I think Chris should post his proof for this post.  Someone is going to power an entire country using his device?  I think this extraordinary claim should require some proof.

Of course, the False Claimant Chris will not do so.  He makes all of these False Claims and has yet to back a single one of them up.
He will make excuses, etc but never offer any proof of his above statement.

Soon, he will claim that Tinman's work is proof of his device...the one that is going to power North Korea.

It is very obvious that illegal drugs and what little brain Chris might have had do not mix.

Bill

[EMJunkie]

It would be nice to continue on with experimental data insted of continuing insults.

Poynt has managed to show the same kind of effect with his sim as i have with my setup. So we know that the effect can be replicated. Now im just waiting for his power disipation ratio's from L2 during the on and off time of L1,and see if he can get a 1:1 ratio like i have. Then come's the agreement between us all that both my DMM's and scope are reading true value's. After that is done,i will present my P/in and P/out value's-but not before. All test from here on in will be done using a set value resistance as the load,and this value is 33 ohms-3 x 100 ohm resistors in parallel

@Tinman - I would advise you to not release any Figure's on IN/OUT

Not here, the GOON Squad will do nothing but ridicule the absolute most ridiculous things...

"The sun was setting so it must be fake", "Diode was too far from the Fett, it must be fake", "Your Scope was the wrong colour, it must be fake", you get the idea... If I were you, I would share privately between trusted individuals.

Not here. Not with the Trolls.

Of course, the decision is yours, and I know you can make your own decisions...

   Chris Sykes
       hyiq.org

[picowatt]

It would be nice to continue on with experimental data insted of continuing insults.

Poynt has managed to show the same kind of effect with his sim as i have with my setup. So we know that the effect can be replicated. Now im just waiting for his power disipation ratio's from L2 during the on and off time of L1,and see if he can get a 1:1 ratio like i have. Then come's the agreement between us all that both my DMM's and scope are reading true value's. After that is done,i will present my P/in and P/out value's-but not before. All test from here on in will be done using a set value resistance as the load,and this value is 33 ohms-3 x 100 ohm resistors in parallel

Tinman,

You might consider trying to drive your primary directly from your FG using sine waves. Try sweeping the FG output between 30KHz and 60KHz, or there about, while watching the inner secondary with your scope.  Try it with the secondaries unloaded at first.  Remember to reset your FG's offset back to zero before doing so.

That steel putty you used, does it retain magnetism noticeably?  That is, if you place a magnet up against it, does that spot retain magnetism sufficiently to lift small objects.  Do you have a scrap piece of the hardened steel putty to experiment with?  I am just wondering how hard or soft, magnetically, that material is.

As for your earlier post regarding your "1:1" or "100%" comments, I am afraid I am a bit confused as to what you meant, and/or how you determined that.  Perhaps you would be so kind to explain that to me a bit further.

PW     

[tinman]

Tinman,

You might consider trying to drive your primary directly from your FG using sine waves. Try sweeping the FG output between 30KHz and 60KHz, or there about, while watching the inner secondary with your scope.  Try it with the secondaries unloaded at first.  Remember to reset your FG's offset back to zero before doing so.

That steel putty you used, does it retain magnetism noticeably?  That is, if you place a magnet up against it, does that spot retain magnetism sufficiently to lift small objects.  Do you have a scrap piece of the hardened steel putty to experiment with?  I am just wondering how hard or soft, magnetically, that material is.

As for your earlier post regarding your "1:1" or "100%" comments, I am afraid I am a bit confused as to what you meant, and/or how you determined that.  Perhaps you would be so kind to explain that to me a bit further.

PW     

I tried using a large neo(n52 grade),and the putty wont retain a magnetic field-is this good or bad?.

As for your earlier post regarding your "1:1" or "100%" comments, I am afraid I am a bit confused as to what you meant, and/or how you determined that.  Perhaps you would be so kind to explain that to me a bit further.

Al explained in the next video. But to try here--> when L1 is powered up for that 5% of the cycle,we get say 1 watt output from the secondary during this 5%. Then L1(the primary) switches off,and we get a further 1 watt from the secondary during this 95% of the cycle.
Now,the average voltage over the whole cycle is 0 volt's,and the average DC current over the whole cycle is also 0 amps. This means that the total power flowing in one direction(during the 5% on time) is exactly the same as the total power flowing in the opposite direction(during the 95% off time) Now people are calling this the inductive kickback(the 95% off time)power,but when have you ever seen an inductive kickback produce 100% of the power of the forward on state power-(our 5% on time)with inductive coupling-transformer effect.

[tinman]

OK
so now i would like to do some power calculations,and would like some input in case i screw this up lol.
First the P/in.
I am going to calculate P/in using instantaneous measurements,and then averaging that out-as my DMM amp meter dosnt like the instant current. So i am using a 10 watt .33 ohm resistor,and scopeing across that resistor to get the instantaneous voltage(below is the scope shot)
So besides the ringing after switch off,i calculate the voltage across that resistor(.33 ohms) to be an average of around 1.7 to 1.8 volts. So our instantaneous current would be 5.15 amps. We average this current out by multiplying it by the duty cycle,which is 5%.
So our average current is 5.15 x 5%=257.5mA. With a large cap between my DMM and the circuit,my DMM reads 251.6mA--so we are close.

Now,the voltage we use to calculate P/in is ?
The voltage of the battery,or the voltage across the coil(L1) during the on time?-->so as we eliminate power disipation of the rest of the circuit.
If it is the voltage across the coil,do we then use that instantaneous voltage value,RMS value,Mean value ,or average value?.