Partnered Output Coils - Free Energy

[picowatt]

Ok,how can i explain this so as it makes sense as to why you cant hook the positive of the output to the positive of the input.

The easiest way to explain it (or demonstrate it) would be to make additional input/output I and V measurements at various output load points.  As .99 suggested, you may not even be at your optimal load point "COP" wise.

Also, as an additional check of input power, can your bench supply output sufficient current to run your device?

PW

[synchro1]

Ok,how can i explain this so as it makes sense as to why you cant hook the positive of the output to the positive of the input.

Build your self an SSG pulse motor-the simple school girl circuit setup.
Now,in stead of connecting the positive of the run battery to the negative of the charge battery,hook the negative of the run battery to the negative of the charge battery,and then try and hook your positive output to the positive of the charge battery,and see what happens.

There is no problem linking the negative on the input with the negative on the output,but you simply cannot hook the positive of the output to the source positive.

@Tinman,

Add a simple output coil to the SSG, wired so the output is above battery voltage, then connect the positive of the output to the positive electrode of the input battery. The battery will accept the charge and run the unit too. I have videos demonstrating this kind of connection working well. It requires the "Voltage Differential".

[picowatt]

That's the gist of what I am trying to say Brad.

If the load seen by the coil can be adjusted (via converter output voltage and current), then hopefully you can loop it AND maximize the Pout/Pin ratio.

.99,

Are you sufficiently satisfied with the in/out measurements Tinman has provided?

Would you care to share any opinions you may have regarding same?

PW

[MarkE]

Tinman thanks for the video.  There are one or two things that can be doen before attempting to work out a self-loop test:

1) If the bench power supply will provide more than 2A, then substitute the bench supply for the battery, and then once the load is connected, dial back the power supply current limit until the circuit collapses.  Record the lowest current setting that the circuit holds up at.  If it is around 0.75A then that gives you additional confirmation that the input current readings are correct.  The input battery voltage reading should already be beyond dispute.  This is what picowatt and .99 are pretty much getting at.

2) If the bench supply can handle the load, then drop using the battery as the bench supply voltage won't droop.

3) See if the apparent OU holds-up with a higher resistance and therefore voltage load.  Two bulbs in series would be useful.  If you need to protect the gate of your MOSFET, a series gate resistor and a  8.2V - 15V Zener diode right across the gate to source connection will insure that the MOSFET doesn't get killed.  For the time being thee is no reason to go beyond 15V on the output side which would be safe for the MOSFET when the load is connected.  The Zener will just protect when the load is disconnected.

4) Reconcile the circuit potentials in preparation for devising a self-loop scheme.  As I interpret your schematic, the input and output are already DC isolated.  So, thee whould be no problems created by jumping the negative side of the battery or power supply to the negative side of the output capacitor.  That is easily checked by seeing if the DMM voltages stay put going from unconnected to connected.  If they stay put, as they should, then all we need is enough voltage while the circuit is still delivering apparent OU.  If this does not work then we will need an isolated circuit.

[picowatt]

Tinman thanks for the video.  There are one or two things that can be doen before attempting to work out a self-loop test:

1) If the bench power supply will provide more than 2A, then substitute the bench supply for the battery, and then once the load is connected, dial back the power supply current limit until the circuit collapses.  Record the lowest current setting that the circuit holds up at.  If it is around 0.75A then that gives you additional confirmation that the input current readings are correct.  The input battery voltage reading should already be beyond dispute.  This is what picowatt and .99 are pretty much getting at.

2) If the bench supply can handle the load, then drop using the battery as the bench supply voltage won't droop.

3) See if the apparent OU holds-up with a higher resistance and therefore voltage load.  Two bulbs in series would be useful.  If you need to protect the gate of your MOSFET, a series gate resistor and a  8.2V - 15V Zener diode right across the gate to source connection will insure that the MOSFET doesn't get killed.  For the time being thee is no reason to go beyond 15V on the output side which would be safe for the MOSFET when the load is connected.  The Zener will just protect when the load is disconnected.

4) Reconcile the circuit potentials in preparation for devising a self-loop scheme.  As I interpret your schematic, the input and output are already DC isolated.  So, thee whould be no problems created by jumping the negative side of the battery or power supply to the negative side of the output capacitor.  That is easily checked by seeing if the DMM voltages stay put going from unconnected to connected.  If they stay put, as they should, then all we need is enough voltage while the circuit is still delivering apparent OU.  If this does not work then we will need an isolated circuit.

MarkE,

How satisfied are you with the in/out measurements Tinman has provided?

I am a bit more confident in the output measurements than I am the input measurements, but even the input measurements are looking pretty solid.  I would like to see some additional verification of the input (bench supply, scope and CSR, etc), but I have to admit, my "probability meter" has moved a bit further...

PW