Overunity.com Archives is Temporarily on Read Mode Only!



Free Energy will change the World - Free Energy will stop Climate Change - Free Energy will give us hope
and we will not surrender until free energy will be enabled all over the world, to power planes, cars, ships and trains.
Free energy will help the poor to become independent of needing expensive fuels.
So all in all Free energy will bring far more peace to the world than any other invention has already brought to the world.
Those beautiful words were written by Stefan Hartmann/Owner/Admin at overunity.com
Unfortunately now, Stefan Hartmann is very ill and He needs our help
Stefan wanted that I have all these massive data to get it back online
even being as ill as Stefan is, he transferred all databases and folders
that without his help, this Forum Archives would have never been published here
so, please, as the Webmaster and Creator of these Archives, I am asking that you help him
by making a donation on the Paypal Button above.
You can visit us or register at my main site at:
Overunity Machines Forum



Partnered Output Coils - Free Energy

Started by EMJunkie, January 16, 2015, 12:08:38 AM

Previous topic - Next topic

0 Members and 216 Guests are viewing this topic.

partzman

Quote from: tinman on October 14, 2015, 08:36:48 AM
Full video is uploading now,but as it is lengthy,it is going to take some time to upload.
I will post it here when done-maybe my tomorrow morning if it takes to long tonight.

In the mean time,here are some scope shots showing 3 different resistive loads across the two secondaries. These scope shots where taken during the testing on the video.

OK, the resistive load tests are now more helpful.  However, one can only assume that the primary voltage across the bifilar wound outer pair is reasonably equal to the voltage shown on the loaded outer secondary. Judging from your description and looking at the core pix, the coupling or K factor for those outer windings should be in the neighborhood of .90-.95 and if so, the primary voltage and the loaded outer winding voltage should be reasonably close. This could definitely leave an apparent anomaly regarding the output of the inner secondary.

Perhaps in the video you show a separate scope measurement of the primary voltage during one of the loaded measurements.

Look forward to the video.

partzman

 


tinman

Quote from: partzman on October 14, 2015, 10:04:16 AM
OK, the resistive load tests are now more helpful.  However, one can only assume that the primary voltage across the bifilar wound outer pair is reasonably equal to the voltage shown on the loaded outer secondary. Judging from your description and looking at the core pix, the coupling or K factor for those outer windings should be in the neighborhood of .90-.95 and if so, the primary voltage and the loaded outer winding voltage should be reasonably close. This could definitely leave an apparent anomaly regarding the output of the inner secondary.

Perhaps in the video you show a separate scope measurement of the primary voltage during one of the loaded measurements.

Look forward to the video.

partzman



Indeed i do.
The primary voltage is almost always the same as the voltage across the  loaded outer secondary. But the inner secondaries voltage when loaded is always almost double that of the primaries voltage. This only changes when the frequency go's above 400KHz. The skin effect then starts to reduce the voltage across the inner secondary,while raising the voltage on the outer secondary. At around this frequency we start to get a phase shift between the two secondaries. At around 500KHz,the phase will shift by 180* between the two secondaries.
!!BUT!! wait until you see the next video-you are not going to believe this,or understand this-->well at least i cannot ATM. I think i have found what im going to call a !Phantom! phase. So i will leave you with this question-->is it some how possible to have the primary 180* out of phase with both secondaries,and also have the two secondaries 180* out of phase with each other?. I only have a 2 channel scope,but when scoping at 500KHz across all the 3 coil's(two at a time),i cannot get two phases to line up-they are all 180* out from each other. I am working on some sort of way to test this so as the two scope grounds would not play some sort of part in this-if they are.

poynt99

Quote from: tinman on October 14, 2015, 08:33:57 AM
And where did i say or infer that it was?.
Obviously the LED being brightly lit also has current associated with that voltage,and that is power.
Well, you stated that it is obvious the one secondary is putting out "far more power" than the other secondary, and you have only shown voltage measurements. We can't assume anything about the power difference between the two outputs, because the one output had no load, essentially. It could not produce enough voltage to turn on the LED, thus it was as if no load was there at all.
question everything, double check the facts, THEN decide your path...

Simple Cheap Low Power Oscillators V2.0
http://www.overunity.com/index.php?action=downloads;sa=view;down=248
Towards Realizing the TPU V1.4: http://www.overunity.com/index.php?action=downloads;sa=view;down=217
Capacitor Energy Transfer Experiments V1.0: http://www.overunity.com/index.php?action=downloads;sa=view;down=209

tinman

Quote from: poynt99 on October 14, 2015, 10:35:30 AM
Well, you stated that it is obvious the one secondary is putting out "far more power" than the other secondary, and you have only shown voltage measurements. We can't assume anything about the power difference between the two outputs, because the one output had no load, essentially. It could not produce enough voltage to turn on the LED, thus it was as if no load was there at all.

Well then,your own statement says im correct in my statement. It is obvious at that point in time,with that particular test,that the inner secondary !was! putting out more power,as the outer secondary wasnt putting out any power,as it only had a voltage across it without current flowing through it. As the LED on the inner secondary was brightly lit,then we can safely assume that there was a voltage across it,and a current flowing through it. So i stand by what i say- it is obvious the one secondary is putting out "far more power" than the other secondary,because the other secondary wasnt putting out any at all.

tinman