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Overunity Machines Forum



Magnetic Engine Video

Started by vineet_kiran, March 07, 2015, 07:57:05 AM

Previous topic - Next topic

0 Members and 6 Guests are viewing this topic.

MarkE

Quote from: vineet_kiran on March 09, 2015, 09:35:08 PM

There is no drag in the setup because shield is moving parallel to the pole on the surface of pole experiencing uniform flux throughout its path. There is only frictional force between moving ball and magnet's surface. This frictional force is very less
because of 'point contact' of ball with the magnet which can be further reduced by lubricating the surface.
If for some strange reason you were unable to detect the drag with your hands, then you should know that is not true.  Instead of using your hands, you can use a weight on a thread that goes over a pulley as the source of force to move the shield.  You can substitute unmagnetized iron or steel bars for the magnet and see how fast a weight pulls the shield to one side, and then repeat first with the magnet restored, and then with both the magnet and the pendulum.
Quote

The question here is not really perpetual motion but it is about overunity.  Is output enrgy more than supplied input energy?
What do you think in that demonstration suggests overunity?
Quote
To know the answer we have to make proper measurements.

If you conduct this experiment you will feel that you will not experience much force on your hand but the oscillating magnet
developes considerable energy due to repulsion.
Why are you comparing force to energy?

MarkE

Quote from: vineet_kiran on March 24, 2015, 09:26:32 AM

Observe the video closely.  Pendulum is not attracted by the shield.  When you cover the fixed magnet with shield, it (shield) cuts off the repelling flux with respect to pendulum hence the pendulum falls towards its mean position by gravity and moves further towards fixed magnet due to its momentum. At this point if shield is moved exposing the fixed magnet, pendulum will again get repelled away.

I have suggested the following points to eliminate the same problem :

1) Keep the fixed magnet very strong and moving magnet considerably weak because a weak magnet cannot get attracted
   towards shield from far distance.

2) Maintain some minimum distance betwee fixed magnet and pendulum magnet because when weak pendulummagnet comes closer
    to the fixed magnet (at maintained minimum distance)  it will not create much change in density of flux with  respect to shield 
    because  shield will be moving on a strong magnet and in a plane parallel to the pole of magnet.
Changing the reluctance gap of any magnet exchanges work.

Low-Q

Quote from: vineet_kiran on March 24, 2015, 09:26:32 AM

Observe the video closely.  Pendulum is not attracted by the shield.  When you cover the fixed magnet with shield, it (shield) cuts off the repelling flux with respect to pendulum hence the pendulum falls towards its mean position by gravity and moves further towards fixed magnet due to its momentum. At this point if shield is moved exposing the fixed magnet, pendulum will again get repelled away.

I have suggested the following points to eliminate the same problem :

1) Keep the fixed magnet very strong and moving magnet considerably weak because a weak magnet cannot get attracted
   towards shield from far distance.

2) Maintain some minimum distance betwee fixed magnet and pendulum magnet because when weak pendulummagnet comes closer
    to the fixed magnet (at maintained minimum distance)  it will not create much change in density of flux with  respect to shield 
    because  shield will be moving on a strong magnet and in a plane parallel to the pole of magnet.
The magnet is attracted by the shield, but the fixed magnet is repelling. The combination makes the repelling force weaker.


Vidar

vineet_kiran

Quote from: MarkE on March 24, 2015, 09:51:25 AM
If for some strange reason you were unable to detect the drag with your hands, then you should know that is not true.  Instead of using your hands, you can use a weight on a thread that goes over a pulley as the source of force to move the shield.  You can substitute unmagnetized iron or steel bars for the magnet and see how fast a weight pulls the shield to one side, and then repeat first with the magnet restored, and then with both the magnet and the pendulum.

I am not talking about friction drag.  When you keep two repelling poles close to each other and hold a shielding plate just above the gap, the shield will be pulled into the gap between two poles with tremendous force. If this drag is present in magnetic engine then your input energy will be equal to or more than output energy. You have to arrange things so as to eliminate this drag.  I am telling this drag is not present in the above setup.  Friction drag is also negligible due to point contact which I feel while conducting the experiment.  You will also feel it if you conduct the experiment.

I know that energy transfer involved is diferent in the above three circumstances said by you.

Quote from: MarkE on March 24, 2015, 09:51:25 AM

What do you think in that demonstration suggests overunity?
Free movement of shield (input) and tremendous energy gained by pendulum (output) due to repulsion shows overunity.

Quote from: MarkE on March 24, 2015, 09:51:25 AM

Why are you comparing force to energy?
I am not comparing force to energy.  When you experience less force on your hand, it means that Force X distance moved by shield = work input is less.   Whereas output energy is high due to strong repulsion between magnets.



vineet_kiran

Quote from: MarkE on March 24, 2015, 09:53:41 AM
Changing the reluctance gap of any magnet exchanges work.

Can you please explain what this has to do with the experiment?