Finally magnetic heater DIY for FREE

[dakanadaka]

Hello good people,
I would like to present you free DIY for copper magnetic heater, We have integrated at our home and its working very well and now we want to share with all of you

So please if you have any tip or question please post it here or contact us direct on https://emolio.com/Magnetic-Heater

Kind regards
Emolio.com

[Paul-R]

What is its performance? How long does it take to heat up its water through, say, 60 degrees centigrade?

[dakanadaka]

here are the data:
from 22 till 95 Celsius of 18 liter oil goes in 17 minutes and I did it with s2 shell oil and it used 0.8kWh

[MarkE]

here are the data:
from 22 till 95 Celsius of 18 liter oil goes in 17 minutes and I did it with s2 shell oil and it used 0.8kWh

0.830kg/liter * 1.8kJ/kg * 18liters * 73C = 1.96MJ = 0.55kWh
0.55kWh/0.8kWh = 68% efficiency

[TinselKoala]

Hmm. Let's see....

0.8 kwh = 800 watt-hours
800 watt-hours x 60 minutes/hour x 60 seconds/minute = 2,880,000 watt-seconds or Joules of energy.

Using rough figures for mineral oil: Specific heat 1.67 J/gram-degree, density 0.85 gm/ml
So 18 liters of oil would weigh about 18000 ml x 0.85 gm/ml = 15,300 gm

To raise this amount of oil by (95-22) = 73 degrees should then take about
15,300 gm x 73 degrees x 1.67 J/gm-degree = 1,865,223 Joules of energy

And 17 minutes = 1020 seconds, so the power needed, if all power goes into the oil, is about 1,865,223 Joules / 1020 seconds = 1829 Watts.

1829 Watts applied for 17 minutes / 60 minutes/hour = 0.28 hour is therefore about 1.829 kW x 0.28 hour = 0.512 kWh of energy.

So, if all applied power goes into heating the oil, it would take about 0.512 kWh. But it actually took 0.8 kWh. So the efficiency is about 0.512/0.8 = 0.64 or 64 percent.


Will someone please check my math?


ETA: I see MarkE has already done the same problem, using slightly different values for specific heat and density.