Inductive Kickback

[MileHigh]

No, the instantaneous power dissipated into the load (the 100Ω resistor) is I²R in both cases ...or 100W.
That would be the case in any constant current source.

The formula P=V*I or P=E²/R could be applied if V represented the magnitude of a voltage source. 
In Milehigh's example, there are no such sources.

Ha! Ha! Verpies you tripped up!   

The initial instantaneous power for the 100-ohm load is 100 watts.   The initial instantaneous power for the 5000-ohm load is 5000 watts.

But of course the total energy in the current pulses for both cases will be the same - no OU.

[verpies]

Ha! Ha! Verpies you tripped up!   

Yes, I did but I will make an example of myself how quickly such mistakes should be admitted.

[verpies]

I just posted that Tinman was wrong about the current flow in an inductor.  Chances are if I didn't post the correction, then nobody would have corrected him. 

You'll get no argument from me. 
I did not even read that post of his, but if I did I would've objected to his statement about the load resistance affecting the current of a constant current source (an inductor in this case).

[citfta]

I'll second that idea of admitting mistakes quickly.  Milehigh I wasn't meaning to say you were wrong with what you said it was the way you said it that could lead some (or many) to believe that you believed in OU from the discharge of a coil.  I am pretty sure you didn't mean that.

[woopy]

Thank's a lot Citfta

Finally somebody answering directly my questions.

So let's go further if you don't mind.

in my question 3
you seems to agree that  the current builds up effectively the magnetic field which propels and gives  the kinetic energy to the rotor.
But is the current or his energy still stored in the magnetic field after the magnetic field has propelled the rotor ?? Any entropy ?

So in my question 4
you seems to say that the input energy could be  used 2 time ?

Thank's very much for your input and for this thread , because i have so much to understand

Laurent