Accurate Measurements on pulsed system's harder than you think.

[tinman]

Those that are following this thread, take some time to think about what you see.
It is said and stated by ohms law that the power disipated by any resistor is determined by the current flowing through it, and the value of that resistor. Now think about the incandescent bulb, and what is needed in order for the resistance of that bulb to increase. Then think about what is needed to raise the light output from that globe, and what must increase in order to raise the dissipated power from that bulb.

When you have the answers to the above, ask your self how is it we see the opposite happening on the scope. How dose ohms law explain more power being dissipated across a resistor with less current flowing through it, and less power being dissipated across it with more current flowing through it.

Can we really dissipate more power from a pulsed resistor or resistive load than we could using straight DC.


Brad.

[TinselKoala]

I think that when you connect the capacitor to the probe side of the bulb, you have contaminated the reading and are no longer reading simply the voltage drop across the bulb.

[tinman]

I think that when you connect the capacitor to the probe side of the bulb, you have contaminated the reading and are no longer reading simply the voltage drop across the bulb.

And if the bulb was removed TK,and we had just the CVR,would not that contamination you speak of still exist at the probe side of the CVR?,as it is just a resistor like our bulb. We have done nothing more than remove one of the two resistors that are in series,and now the cap is conected to the probe side of the CVR.

What is this contamination?-->how can a voltage be seen across a resistor that dosnt actually represent the true voltage across that resistor?.

I will get deeper into this as we go-->this (what you call) contamination.
But first a few more video's on testing done to find the answer. Next wee will be connecting a DC current source to our bulb,and increasing the voltage until  we get the same power output from our solar panel. We can then see what is truth,and what is not. I will replace the current resistor that is across the solar panel with a higher value one,so as we can get a more accurate voltage reading across that resistor. Then we will run the pulse motor again,and obtain our two reading's and values. then we send a DC current through the light bulb,and keep increasing the voltage until we get the same output from the solar panel.


Brad

[TinselKoala]

OK, I've essentially duplicated your results, using a " no-Bedini Atoll " circuit as illustrated below.

I found that the value of the inductor-resistor combination determines whether the bulb gets brighter, or dimmer, when the capacitor cliplead is connected.

The values shown in my circuit image produce _no change_ in the visible bulb brightness when the clip lead is connected, even though the scope shows over twice the power through the CVR-bulb when the cap is connected than when it is not.

A slightly higher resistance produces less brightness when the cap is connected; a slightly lower resistance produces more brightness when the cap is connected.

With 21.3 ohms, it is easy to see that the bulb is less bright when the cap is connected than when it is not.

[TinselKoala]

I've made a video showing my results but it will probably be an hour or so before it's ready to view on YouTube.

I don't know if my "contamination" idea is correct or not. It is certainly an interesting effect that TinMan has discovered, and as my testing shows it doesn't depend on a Bedini motor or any pulse motor at all, just a pulsed circuit. I don't know if the inductor is even necessary either.

Ah... where is MarkE when you need him. Sigh. He'd set us straight on this, I'm sure, but alas it is not to be.