Perpetual Mobile with compliance of the law of conservation of energy

[abv]

Perpetual Mobile concept. Where is the mistake here?

Everyone knows that "perpetual motion machine" can not be created. This is contrary to the law of conservation of energy. Indeed, the excess over 100% efficiency gives energy from nowhere. Energy possible get as much as was spent or even less because part of the energy is lost in the conversion process.

All this is true for closed systems where the balance of forces always will stay in equilibrium state and any energy transformation within a closed system will be less than 100% efficiency. However, if look in a broader scale, than possible create linked closed systems which will use one shared object. These linked closed systems use same shared object simultaneously. Other words, during interactions in these closed systems, the internal forces inside them will not influence each other. However, changes of physical parameters of object what was done in one system will change the balance of forces in the other linked closed system. Therefore, even with the law of conservation of energy in a closed systems, the work will be induced by changes of physical parameters of the object to restore the balance of power in a closed system.
More details here: https://somephysicsideas.wordpress.com/2016/01/30/perpetual-mobile/

[sm0ky2]

I have read your webpage, and what I notice upon first glance, is that you are missing 1/2 of the work function in the first system.
It is acknowledged, as potential gravitational energy, at the end of the cycle in the second system.

Compression of the gas inside the balloon consumes an energy, lets call it the "compression energy".
This heats the gas, so in order to maintain an adiabatic compression, heat must be taken out of the gas and stored.
the expansion energy is essentially equal to the compression energy and can be directly obtained by allowing the balloon to expand.
This cools the gas, and to maintain an adiabatic expansion, the stored heat must be put back into the gas to maintain constant temperature.
While it may be a painful task to physically build this, the physics are pretty straight forward.
If we had a material with a low enough coefficient of thermal conductivity, (well insulated)
and a near perfect heat pump, eliminated friction, etc. we could (in theory) make a process 100% efficient.

Your second system is described adequately enough that I don't need to tear it apart. But you are left with an energy value.
E =mgh, where m is the mass of the "load", g is gravity, and h is the height the load was lifted to.
why?

All of these equations, all of the constants involved, their proportional relationship,
these things depend upon an earth specific human condition.
In other words, all of these experiments are assumed to take place at Sea Level, and 1 Atm of pressure.
The second part is what you forgot to take into account.

There is a work function, to displace the atmosphere, and cause buoyancy.
This is proportionally equal to the gravitational potential as a result of the buoyant force over distance.
Buoyancy is not "infinite" in height. In water it appears that way because we can make pressure differences that result in a height greater than the water column.
This is not the case in air, there is a point where (if the balloon doesn't expand with height) the buoyant force will equal out with gravity.
This change in energy (e=mgh) is exactly the same energy put into the work function that displaced the air in the first place.

[sm0ky2]

to further understand this, compare it to two fluids of different density.
one will float on top of the other.

now, add a 3rd different density fluid to the container, and you will see layers.

the atmosphere is the same way. there are layers of different density. Water sits on the bottom, heavy gasses like nitrogen tend to sit near sea level (when there is little wind).

add varying temperatures and pressures, and our sky can contain hundreds of unique specific gravity layers.

If you had several balloons, each of equal mass, and equal displacement (volume). maintained an equal temperature.
and released them, to allow buoyancy to take over.

You would find that the balloons all settle to the same height. like they were a fluid of specific density.
and that is exactly what they can be viewed as.
Their equivalent density balances out with that of the air around it.
Heavier air is below, and lighter air is above the balloons.

this is affected by the load, a series of loaded balloons will assume a lower maximum height.
in fact you can do this with a helium balloon in your living room. Simply increase the load to slightly less than the maximum load the balloon can lift.
You can get it to balance at a specific height within the space between your floor and ceiling.
Add more load to make it float lower, decrease the load to make it float at a higher level.

If you were to now expand and contract this 'loaded' helium balloon, the change in potential energy, as observed by the height of the load:  will correspond precisely with the atmospheric displacement component of the expansion energy during the expansion phase.

ps - you cannot regain the  energy during the compression phase at the top of the buoyant column.
the atmospheric pressure is proportionately lower at this height. there is no more potential to compress, which is
why the buoyant force balances out at this point.

[abv]

If we had a material with a low enough coefficient of thermal conductivity, (well insulated)
and a near perfect heat pump, eliminated friction, etc. we could (in theory) make a process 100% efficient.

If you were to now expand and contract this 'loaded' helium balloon, the change in potential energy, as observed by the height of the load:  will correspond precisely with the atmospheric displacement component of the expansion energy during the expansion phase.

As it was mentioned the efficiency of first closed system is 100%. So, the stored energy from gas expansion process can be used for gas compression process.
In this case, when balloon with load is lifted on certain height, the gas compression process will use energy what was stored from gas expansion. However, the potential energy of load can be used as extra energy.

[sm0ky2]

As it was mentioned the efficiency of first closed system is 100%. So, the stored energy from gas expansion process can be used for gas compression process.
In this case, when balloon with load is lifted on certain height, the gas compression process will use energy what was stored from gas expansion. However, the potential energy of load can be used as extra energy.

you're still missing it.....

It takes MORE ENERGY to expand it at lower altitudes.
the DIFFERENCE in ENERGY is the SAME as the BOUYANT WORK FUNCTION!!!!!!

there is no "extra energy".....  the work done to lift the load was already consumed by the expansion process
PRIOR to the lifting.....