MH's ideal coil and voltage question

[tinman]

Brad:

I will repeat this a second and last time.  The addition of the resistance to the simulation is to solve a constraint in the way the software works.  It has nothing whatsoever to do with what you are referring to.



You literally have been given a partial correct answer from partzman in two forms.  Someone else earlier in the thread described an ideal inductor behaviour perfectly.  It looks like it's going to take a few more days before you come round and it may have to end up being a forced spoon feeding session from a guru.

MileHigh

MH
Maybe you can work out the L/R time constant of an ideal coil.
As Poynt stated,and as i stated,it will then be 5/0=infinity.
You have already stated that there is no time constant,and the value could be infinity or undefined-correct?,or do i have that wrong?.

If it is infinity,then there is going to be no current flow into the ideal inductor-correct?

So unless you know some sort of math that allows a division of 5/0,and provides a value we can work with,then i will stick with my claim.

You are in for an unpleasant surprise when Poynt comes back.  You think that both of you are on the same page but you are not.  Like I said, I can't explain his quote but in due time we will find out.

Well i dont believe that Poynt would lead me down the garden path,or post sarcastic results,just because that is what i believe. Sure,we have had our moments,but we have also had our times where we get along just fine,like in the Lewin topic not long ago. I listened to what he was saying,and carried out the test as he stated,and it resulted in being exactly what he said it would be. There is always going to be times when we dont agree on something,but when it comes time to work on thing's like this,then we should both be striving toward a correct answer and outcome.

Brad.

[MileHigh]

Brad:

<<< If it is infinity,then there is going to be no current flow into the ideal inductor-correct?  >>>

Here is something for you to ponder:  A straight line is a circle with a radius of infinity.

[Magneticitist]

I also want to point out in a non sarcastic manner, that this is what it's all about. despite our little beefs we are trying to put our minds together to debate and brainstorm what's going on here... From the EE professionals to the casual tinkerers it's not so cut and clear... this is how complex electricity can be..

I'm not saying a simple agreeable answer is impossible... but clearly if one 'side' has yet to clearly come to an agreeable conclusion then it must be, at the very least, a little confusing.

[Magneticitist]

They say fixed source meaning that the voltage will not change under load.  They don't say anything else.

well in all honestly my mistake then.. but I took 'fixed source' as being utterly fixed.

[tinman]

Brad,

I don't support your answer regarding the inductor acting like an instantaneous short. Just because there is no current flow, doesn't mean the load presented to the voltage source is no longer "inductive".

There is only one answer, that being the inductor will essentially look like a perpetual "open" to the voltage source. At least that is my thinking on this until MH corrects me, and I welcome being corrected if I am in fact wrong on this.

OK,so here is the part in that reply i dont understand.
If the inductor looks like a perpetual open (circuit i guess?)to the voltage source,then what is the load?

Brad