MH's ideal coil and voltage question

[poynt99]

Perhaps we have a solution for the Emf = Cemf issue using some basics.
 
Refer to the image below. Now picture a bar magnet approaching the coil from the left with it's north pole facing the coil. From Lenz we know an Emf will be produced in the coil that opposes the approaching PM with the polarities as shown.  I think on this we can all agree.  Note that the current flow is conventional.

Now the question is, does this induced Emf produced coil current produce a Cemf to itself?  IMO, no as there is no evidence to support this.

As long as the induced emf results in a current flow, wouldn't there will be an associated cemf? I think yes.

[poynt99]

Awaiting your responses Brad.

[minnie]

As long as the induced emf results in a current flow, wouldn't there will be an associated cemf? I think yes.

  That's what I'm a thinkin'
          John.

[partzman]

As long as the induced emf results in a current flow, wouldn't there will be an associated cemf? I think yes.

So we have another Cemf (Cemf2) produced by the current in the coil that is generated by the original Cemf from the approaching PM? If we have two Cemfs produced by the approaching PM, what is the phase of Cemf2 in relation to the original Cemf? IMO, either phase of Cemf2 is problematic in that either attraction or repulsion is increased in regards to the PM.

This is the crux of the issue IMO.

pm

[poynt99]

So we have another Cemf (Cemf2) produced by the current in the coil that is generated by the original Cemf from the approaching PM? If we have two Cemfs produced by the approaching PM, what is the phase of Cemf2 in relation to the original Cemf? IMO, either phase of Cemf2 is problematic in that either attraction or repulsion is increased in regards to the PM.

This is the crux of the issue IMO.

pm

Do you not agree that a changing inductor current results in a changing B field around the inductor? If so, then would self-induction not be present?

It seems to me that regardless how the emf is produced (either by applied voltage or induced magnetically), there would be a corresponding self-induced cemf.