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Overunity Machines Forum



MH's ideal coil and voltage question

Started by tinman, May 08, 2016, 04:42:41 AM

Previous topic - Next topic

0 Members and 7 Guests are viewing this topic.

Can a voltage exist across an ideal inductor that has a steady DC current flowing through it

yes it can
5 (25%)
no it cannot
11 (55%)
I have no idea
4 (20%)

Total Members Voted: 20

poynt99

Sorry,

I thought it was obvious that "burn" implied energy dissipated in the resistor as heat.

In terms of answering yet more of your questions, you've not yet acknowledged that you understand or agree (or not) with my explanation in that post as to why the resistor value does not matter when a pure resistance connects the two caps.
question everything, double check the facts, THEN decide your path...

Simple Cheap Low Power Oscillators V2.0
http://www.overunity.com/index.php?action=downloads;sa=view;down=248
Towards Realizing the TPU V1.4: http://www.overunity.com/index.php?action=downloads;sa=view;down=217
Capacitor Energy Transfer Experiments V1.0: http://www.overunity.com/index.php?action=downloads;sa=view;down=209

Magluvin

Quote from: poynt99 on May 28, 2016, 10:02:16 PM
Sorry,

I thought it was obvious that "burn" implied energy dissipated in the resistor as heat.

In terms of answering yet more of your questions, you've not yet acknowledged that you understand or agree (or not) with my explanation in that post as to why the resistor value does not matter when a pure resistance connects the two caps.


Im thinking that the heat from the resistance only costs time. Time for the cap to fully distribute half of its electron count imbalance to the other cap. If it is ideal, then there is no time in the transfer according to what is said, and with resistance, the transfer takes longer the higher the resistance is.

So thats my answer, and my earlier questions deal with it specifically.

You said something much earlier on the electron count imbalances Im speaking of.  Dont remember. It was more of a question about if Im sure about the counts meaning anything.

But maybe you dont believe the electron imbalance between cap plates determines its particular voltage level accurately for a particular cap value. Not sure. ??? If not, could you explain why?

Mags

Magluvin

Quote from: Magluvin on May 28, 2016, 10:51:44 PM

Im thinking that the heat from the resistance only costs time. Time for the cap to fully distribute half of its electron count imbalance to the other cap. If it is ideal, then there is no time in the transfer according to what is said, and with resistance, the transfer takes longer the higher the resistance is.

So thats my answer, and my earlier questions deal with it specifically.

You said something much earlier on the electron count imbalances Im speaking of.  Dont remember. It was more of a question about if Im sure about the counts meaning anything.

But maybe you dont believe the electron imbalance between cap plates determines its particular voltage level accurately for a particular cap value. Not sure. ??? If not, could you explain why?

Mags

"Im thinking that the heat from the resistance only costs time. Time for the cap to fully distribute half of its electron count imbalance to the other cap."

Actually, not just a cost of time. We did waste the energy doing the ideal cap to cap by not using the action of the current flow. When there is resistance, I agree there is heat. Just to be clear....

My whole point is, I dont believe that resistance is responsible for the 50% loss in the cap to cap example. If we needed heat from the cap to cap device, then we get it. If we use a motor in series with the 2 caps till the caps at 5v each, then we got motor output during the transfer and we end up with 5v in each cap. We used the transfer. We used the missing energy. But Im still thinking that the ideal caps in these situations and cap to cap would still end up with 5v per cap when all is said and done. And Im putting my money on the electron count to prove so.

2000 Electron Count Imbalance of an ideal cap to a 0 imbalance cap should divide the imbalance to 1000 imbalance in each cap. 

Now if we were to say that the ideal cap is 2000 ECI and we do the cap to cap, how could it be that we end up with 1400 ECI per cap? 10v to 7.07v each?

Now in your much earlier question I would have to think maybe you agree on the imbalance but think that 2000 ECI to 1000 ECI would equate to 10v to 7.07v each.  Well if that is the case, then that would mean we lost some of the beginning ECI once the caps balance out in the real world cap to cap deal. If so, where did they go?


Mags

minnie




   Capacitor = potential .
   Inductor = kinetic.
   Sounds good to me.

poynt99

Mags, I'd be happy to answer your questions and respond to your answers, but I simply can't make much sense of them. Probably my failing.

As far as I'm concerned, I've given you the info you need to sort things out in regards to the cap to cap transfer problem.
question everything, double check the facts, THEN decide your path...

Simple Cheap Low Power Oscillators V2.0
http://www.overunity.com/index.php?action=downloads;sa=view;down=248
Towards Realizing the TPU V1.4: http://www.overunity.com/index.php?action=downloads;sa=view;down=217
Capacitor Energy Transfer Experiments V1.0: http://www.overunity.com/index.php?action=downloads;sa=view;down=209