Increase the potential energy without any energy

[activ25]

You don't understand. The device is with the white disk always. It is for understand a different easier device: without the white disk, like that it proves the sum of energy is conserved, it proves there are no others energy than the work of the walls and the potential energy of the springs.

1/ Device number one: without the white disk. It proves the sum of energies is constant. The principle is correct.

2/ Device number two; with the white disk. I calculated the sum of energies from the data of the device number one. Look at the equations. I took in account,:

- the potential energy of the springs at start and at final, reduces in comparaison to the device number one because there is the white disk, reduces of the same value at start and at final (the force of the springs don't depend of their length)
- the work of the walls, is the same than the device number one
- the extra energy from the difference of length L1>L2
- that's all, the white disk don't need (or give) an energy
- move out and in the spheres don't need (or give) an energy

When I speak about the negative energy it is to note that the sum must be constant, not positive AND not negative. Because there is no friction so the energy is in work in something or in a potential energy.

[activ25]

"You are NOT describing the how's,, how does the spring\sphere move down from L1 to L2,"

I use an external device (called it C_device for control device). C_device is a perfect device, no loss. It control the device because my device is unstable. The C_device gives the energy my device needs and recover the energy it can. It is not very important, with what you recover the energy, when the sum of energy is not zero, you can use it like you want.

[activ25]

Thank you.


Now can you tell all of us what those exchanges are for the c_drive,, sure it is ideal and suffers no losses itself,, but it will need to supply energy to move the sphere\spring down from L1 to L2 so it can then extract that exact same amount of energy out of the spring\sphere at L2 and then insert that spring\sphere back in at L2.


Your c_drive is the YOU I refer to as YOU putting in the energy.

C_device receives a sum of energy equal to 'e', like I wrote in the equation. 'e' is the sum of all difference of length (by unit of force) of the springs (only the spring which a sphere is moving out/in). I don't need to calculate all 'e' because for a small angle of rotation of the device (example 1°) it is logical the difference is always L1>L2. So 'e' cannot be equal to zero for a small angle so the sum of energy is not conserved, the goal of this device.

[activ25]

When energy is not conserved what you are being told is that you are NOT including all things.


Energy will ALWAYS be conserved because energy is a tool made by man so that things that are not the same can be compared,, it is a tool,, this very tool is telling you that you do not have all things considered.


Your c_drive needs to move the spring\spheres down from L1 to L2,, it needs to add that energy INTO the system so that it can then take it back OUT,, this is what the tool of energy is telling you.
It is telling you what the c_drive is doing,,it is putting in "e" and also taking "e" out.


O.U. will only be O.U. until the unknown component is identified, studied, and understood, then it will be a known process.

Pass from L1 to L2 = win an energy. My device don't need in theory an external device. So in theory, the sum of energy is not conserved. And it will be the same in practice with an external control device.


"Energy will ALWAYS be conserved " is like the image.

[activ25]

The springs don't increase their potential energy, they decrease... I win this energy L1>L2.

Well then,, I guess the only thing left for you to do is to build

No, this theoretical device is there to prove the conservation of energy (like others conservations) is bullshit. I have anothers ideas complex to calculate but easier to build.