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Overunity Machines Forum



Magnets, motion and measurement

Started by Floor, October 31, 2016, 09:11:43 PM

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0 Members and 3 Guests are viewing this topic.

Floor

My test bench is set up, level and calibrated.   AT this point all that I am doing, are rough measurement sets and playing around with it ( just to warm up).

I still need to clean up / test the triple beam balance I recently acquired.  Thanks


In the interim I make this challenge to all readers....



                                                                                                                      CHALLENGE
         
In the method which I demonstrate, the output (by falling) work  is undone during each cycle, but, the input (by lifting) work is also undone during each cycle.  The output "work" is more than twice the input "work".

The operation you present, must be indefinitely cyclically repeatable. The use of levers and springs is permissible.  In short, demonstrate the cyclical lifting of a greater weight upon the long side of a lever by using a lesser weight upon the short side of that same lever or...... some other mechanically equivalent device which uses mechanical springs.

Mechanical output must exceed mechanical input in each cycle, even if  that mechanical output may be undone during each cycle (sums to zero). A mechanical spring or springs may be used in the device.  Remember however, the input mechanical "work" in each cycle, must always be less that the output mechanical "work" during that cycle.

            Meet or exceed the below, or at least exceed 1 to 1.
Cause 115 grams to be lifted 40 units of distance against gravity, by the lowering lowering of 100.75 grams 22 units of distance by gravity.
          In the exemplary demonstration I provide.......
The force ratio is 100.25 grams input to 115 grams output.
The mechanical displacement ratio is 22 units input to 40 units output.
                        The work in to work out ratio is....
      100.75g x 22 = 2216.5 input.   115g x 40 = 4600 output.
As I said (in my exemplary device), the work done both as the lifting and the falling is undone in each cycle.


        HERE @      https://www.dailymotion.com/video/x7b3x9a

   floor

ayeaye

I must say that i used matchboxes in my experiment, to put a big magnet under an angle vertically. The key is that there has to be three points of support, in such a way that when trying to move the upper corner of the magnet horizontally, there is enough resistance in both directions.


norman6538

Excellent workmanship Floor but I don't get this point. You said

"As I said (in my exemplary device), the work done both as the lifting and the falling is undone in each cycle."

To me the basic cycle pattern is
1. set the device into potential work out which requires some work in.
2. that work out is released and can be seen and measured.
3. reset the device so that 1-3 can be repeated  which requires some work in.

Please help me understand this a little more.
Thanks for all of your diligent work.
Norman


Floor

@Norman6538

The device is sitting there..

          As in the video, starting position.

There is a 115 gram weight hanging from the rotating unit's pulley. 
That weight is in its HIGHEST POSITION (0 degrees of rotation on the rotating unit's scale).
Magnetic force between the two magnets, is holding it in that highest position.
This is because the force to cause the rotating magnet to rotate to the vertical and 0 degree position is is at its
maximum. 
This is because the rotating and the sliding magnets are nearly touching. 
The closer these two magnets are to one another the more force there is to cause that rotation.


!. INPUT .... Pushing upon the sliding action (with the finger) lifts the 105 grams 22 units of distance (via the pulley benieth the sliding unit).
Actually this is only 101.75 grams lifted, considering that there is a counter weight that pulls / keeps the thread
that connects the sliding unit to the sliding unit, scale dial pulley. 
The COUNTER WEIGHT thread wraps in the opposite direction on the sliding unit, scale dial pulley, and keeps the thread taught.
(opposite wrapping direction to the thread connecting the SLIDING UNIT to the sliding unit, scale dial pulley,
That counter weight is 4.25 grams  (105 g minus 4.25 grams =100.75 grams).

That pushing of the sliding unit, with the finger also separates the sliding magnet from the rotating magnet

2. Output # 1...  The weight upon the Rotating unit falls.
This is because the two magnets are now more distant from one another.
That weight is 115 grams and it falls 40 units of distance.
This output occurs at the SAME TIME as does the input from the finger push.

3. Output # 2 occurs as the force from the finger is released (the sliding unit weight falls to its original position).
This output occurs at the same time as does the lifting of the rotating magnet
(by magnetic force between the two magnets) as the falling of the weight benieth the
sliding unit draws the sliding unit magnet back toward the rotating unit magnet.

   best wishes
                floor

norman6538

Floor thanks for your explanation.
This is how I understand it now.

  UOW is units of work

1. push magnets together with 2216.5 UOW (100.75  grams 22 units distance)
    (105 g weight minus 4.25 grams =100.75 grams).

2. making  4200 UOW by twisting/rotating/lifting
    (105 grams lifted 40 units of distance)

3. release the sliding unit to reset itself (preloaded/balanced to pull back )
4. repeat step 1 using 2300 UOW from the jump start first step 1. above.

To make it a  self runner then lift 2 weights
1. 2300 UOW (57.5 g x 40 units) from the first step 1 above.
2. 1900 UOW (47.5 g x 40 units) totally extra for external use...

BUT  some of the 1900 UOW will have to be used for switching the weights
from lifted to using.....which I call switching.  That is the step that always snagged me.

Norman