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Overunity Machines Forum



TD replications

Started by Floor, November 18, 2016, 11:14:23 AM

Previous topic - Next topic

0 Members and 27 Guests are viewing this topic.

gotoluc

Quote from: conradelektro on February 10, 2017, 01:19:10 PM
If you do a replication please do compare output-POWER and input-POWER (and not FORCE or WORK)

See: http://overunity.com/17097/magnet-force-shield/msg499715/#msg499715 (concerning POWER versus WORK, TIME is of the essence)

FORCE

WORK = FORCE * DISTANCE

POWER = WORK over TIME

Greetings, Conrad


Dear Conrad,

Please reply to the simple question (in bold) of this post:

Quote from: gotoluc on February 10, 2017, 10:44:40 AM
Dear Conrad,

Lets look at a test device which can test your distance time beliefs.

Test device parts needed:
A DC electric motor which has a flywheel attached to its shaft and use of photo switch to turn the motor on and off.

First test:
We attach a scale to the outer circumference of the flywheel and adjust the current to the motor so it can pull 34 grams.
Then we adjust the photo switch to power the motor 110 mm distance of the flywheel outer circumference.
We note of the RPM in this condition.

Second test:
We attach a scale to the outer circumference of the flywheel and adjust the current to the motor so it can pull 538 grams.
Then we adjust the photo switch to power the motor 11 mm distance of the flywheel outer circumference.
We note of the RPM in this condition.

If your belief is correct, the RPM should be greater on the first test compered to the second test, correct?

Regards

Luc

telecom

Quote from: gotoluc on February 10, 2017, 01:28:36 PM
That's the beauty of this design, there is no work "balance" needed for the next position (cycle)... as the fist cycle goes through the next cycle is right there and needs exactly the same as the first cycle.

Luc

So, to return the linear stage to the initial position will take the same work, and the linear stage will generate the same work?
Approximately 1.5 times more than input?

dieter

How about to slap a rudimentary crankshaft together, using the 11mm push over leverage to turn the wheel? Would probably be less timeconsuming than all measurements an defendings ^^

gotoluc

Quote from: telecom on February 10, 2017, 02:12:30 PM
So, to return the linear stage to the initial position will take the same work, and the linear stage will generate the same work?
Approximately 1.5 times more than input?


You don't need to return the linear stage to the initial position. The rotor magnet alternate N-S-N-S which creates the back and forth linear action which give 11mm linear force (538 grams) in each direction. No rest needed.

Luc

conradelektro

Quote from: gotoluc on February 10, 2017, 01:38:16 PM
Dear Conrad,

Please reply to the simple question (in bold) of this post:

If your belief is correct, the RPM should be greater on the first test compered to the second test, correct?[/size]

Luc,

it is not a simple question and I have no simple answer. I have not studied physics (only mathematics and law) therefore I would have to read up about flywheels in my physics text books. This would take hours which I am not prepared to put in today.

The quick answer: I do not see the connection between a flywheel and your machine. A flywheel is continuous movement. Your machine has two movements, a continuous turning movement (like a flywheel, if you want to see that probably false analogy) and an intermittent reciprocal movement.

Very important and constantly overlooked fact: your sledge also pauses during its movement (cycle, reciprocal movement). And during the pauses it does not do work.

Like a LED that is driven intermittently, whose average light output is less than a constantly driven LED (with the same Voltage and Amperage, this is what dimming is all about), your sledge outputs less energy than thought if the pauses are taken into consideration. (And exactly there I see no continuous fly wheel).

So, please forgive me that I do not want to study fly wheels at the moment. Your fly wheel example might have the answer "yes", but there is no Konnex to your machine

Just think for a moment, it is important how long work is done. Only when knowing how long a certain work is done one knows its power output (energy).

I have said more than often: POWER is WORK over TIME. If there is no time, there is no power (when the sledge pauses). A power company sells Watt-Hours and not Watt. You have to get the difference between Watt and Watt-Hours (between Work and Power or Energy). Which in your case is the difference between Gram or Gram-Hours. Or, if we would do the conversion from Gram to Joule, it is the difference between Joule and Joule-Seconds (or Joule-Hours if you want).

This is not my opinion, this is a fact. Everybody would complain if his work would not be paid by the hour. It matters very much how many hours you do your work. The average power output of your work is less (per hour) if you drink coffee for 15 minutes every hour (a pause of 15 minutes every hour). Your power output will be 25% less. All employers know that simple fact. All power companies know that it is important how long you switch on your loads.

Greetings, Conrad