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Overunity Machines Forum



TD replications

Started by Floor, November 18, 2016, 11:14:23 AM

Previous topic - Next topic

0 Members and 7 Guests are viewing this topic.

Floor

The force is considered as a constant  < 5 grams over the entire 1 and 7/8 inches
input stroke.

1 inch = 25.4 millimeters

25.4 millimeters = 0.0254 of a meter
... ... ... ... ... ...
7/8 of an inch = 0.875 inches

0.875 of a inch = 22.225 millimeters

22.225 mm = 0.02222 meters
... ... ... ... ... ...
1 and 7/8 inches =  0.04762 of a meter                                                                                       
... ... ... ... ... ...
1 gram of weight (on earth) =  0.0098066500286389 newtons of force

5 grams of weight (on earth) = 0.0490332501431945 newtons of force

                newtons of force time meters = joules of energy or work.

0.049 newtons x  0.04762 meter = 0.00233 joules of work.

                                                 first result is 0.00233 joules.
               BUT IN SIMPLIFYING
If we skip the conversion to joules and just refer to the 3 inputs and the single output
energy as "units" we get

1 7/8 inches x 5 grams = 9.375 units
  or
1.875 inches x 5 grams = 9.375 units

There are two inputs like this.  One at the starting end for the output stroke and
the other for after the output stroke.

2 x  9.375 units = 18.75 units input
... ... ... ...
The input to re position the output magnet to the start position, along a parallel path (exterior to
the magnetic field) is here considered as 0 units of input.
... ... ... ...
18.75 + 0 = 18.75 units total input.
... ... ...
It should be clear that an out put greater than 18.75 is easy to obtain ?

Our previous test output measured as 144 units total output, the work in to work
out is now 18.75 to 144, and that is O.U.

Note... in this present configuration the actual output is much higher. This is because
of both a longer output stroke and a greater magnetic force over the course of that stroke

   best wishes
            floor

Floor

If anyone thinks the output stroke DIRECTION is incorrectly illustrated (Below),
pick up two magnets and see for your self.  I know it might seem strange, that the
magnet would move in that direction, but is does.

best wishes
   floor

Floor

That's it.  An O.U. device on a single page. ;)

I'm tired, see you all later.

   peace out

norman6538

Fantastic Floor.

I do not understand this part
"the input to re position the output magnet to the start position, along a parallel path (exterior to the magnetic field) is here considered as 0 units of input."

But down the road you have enough  extra to make a self runner but the "clock mechanism" to do that is complex.

What I wanted to to was to use a small weight to lift a larger  output weight and then use some of the  output  weights to feedback as input leaving extra weights for usable power.. So you can manually move those weights into their positions to do that in order to demonstrate the real work in vs work out and there will be no arguments. Then you can move on to automate it into a self runner.

But first someone needs to verify your setup. Unless I get extra time I doubt I will be that person.

Norman

Floor

There are 3 input motions. Basically the output magnet is walked around
3 sides of a square or rectangle, the fourth side the "output side", walks itself.

one side is removal... input
next it moves along to the far end while outside the magnetic field...  0 input
against magnetic forces.
next is in insertion... input

This video shows the motions, although it is of the previous design.

https://www.dailymotion.com/video/x80nhtf