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Overunity Machines Forum



re: energy producing experiments

Started by Delburt Phend, February 04, 2017, 09:31:19 AM

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0 Members and 3 Guests are viewing this topic.

Low-Q

Quote from: Delburt Phend on February 21, 2017, 09:25:07 PM
If you apply 10 newtons for one second to a mass of 10 kilograms you get 5 joules of energy.  (½ mv²)

If you apply 10 newtons for one second to a mass of 1 kilograms you get 50 joules of energy.

If you transfer all the motion of 10 kilograms moving 1 m/sec to one kilogram; the energy changes from 5 J to 50 J.

This is exactly what happen in the video; The motion of a massive object is given to a small object and the small object gives the motion all back; twice. The same quantity of motion is contained in the small object as is contained in the large object.

The small object with the same quantity of motion contains significantly more energy.
I can clearly see the confusion here. Your equation of kinetic energy is correct, but I think you have missed something out. Energy IS ALWAYS conserved, so there MUST be a misconception somewhere. I can't point it out for you, but I strongly believe you've missed something out.
I'll digg into my old papers, and maybe I find something that explains it all.




Low-Q

Now I think I got it.
If you use the 10kg mass to transfer energy into the 1kg mass, the heaviest weight does not loose ALL its kinetic energy, but only some is transfered to the lightest weight.


If you have two steel spheres in space. One small and one large that has 10 times more volume.
If the small sphere is stationary, and you take the large sphere and push it with 1m/s head on to the small sphere. What happens in the collision?
Does the large sphere stop completely, and the small sphere shoots away in 10m/s? That is what your idea suggests.


Vidar

Delburt Phend

That is absolutely correct Q; that is absolutely what happens.

But instead of using one ten kilogram sphere you use two five kilogram spheres at 180° on a light rim. Wrap a string around the rim from each of the 5 kilogram spheres; place one kilogram on the ends of the two equal length strings. We now have 12 kilogram on a very light rim.  Spin the rim at one meter per second; and release the two one kilogram masses. When released the two one kilograms spheres will unwrap and the two five kilogram spheres will be quickly stopped. The two kilograms will have all the motion that previously existed in the 12 kilograms. They will have 12 units of momentum; because the 12 kilograms had 12 units of momentum. The two spheres will be moving 6 m/sec; for an energy increase of 600%

The video proves that this is what happens; because the spheres restore all the motion back to the cylinder twice. And the cylinder had been stopped twice. only Newtonian momentum can do this.

I could have stayed with 10 kilograms by using two 4 kilogram masses at 180°.

But instead of using one ten kilogram sphere you use two four kilogram spheres at 180° on a light rim. Wrap a string around the rim from each of the 4 kilogram spheres; place one kilogram on the ends of the two equal length strings. We now have 10 kilogram on a very light rim.  Spin the rim at one meter per second; and release the two one kilogram masses. When released the two one kilograms spheres will unwrap and the two four kilogram spheres will be quickly stopped. The two kilograms will have all the motion that previously existed in the 10 kilograms. They will have 10 units of momentum; because the 10 kilograms had 10 units of momentum. The two spheres will be moving 5 m/sec; for an energy increase of 500%

Low-Q

I think you're ready to build a device that is possible to measure all events. Because the example of the balls in space (space balls haha) isn't correct. The large ball will not stop completely, but if it did, the small ball would bounce away with approx 3,162277m/s - not 10m/s.
3,162277 happens to be the square root of 10 - square root of the relationship between the two weights of respectively 1kg and 10kg. The formula for kinetic energy is a quadratic equation (or do you say "second degree equation"?), remember?

telecom

Quote from: Low-Q on February 22, 2017, 02:18:35 AM


If you have two steel spheres in space. One small and one large that has 10 times more volume.
If the small sphere is stationary, and you take the large sphere and push it with 1m/s head on to the small sphere. What happens in the collision?
Does the large sphere stop completely, and the small sphere shoots away in 10m/s? That is what your idea suggests.


Vidar

DP makes an arrangement where he ensures transfer of all the momentum when
string unwraps.
In your case, when 2 bodies hit each other, it doesn't happen.