re: energy producing experiments

[Delburt Phend]

I added 216 grams to the 972 gram cylinder: so now the cylinder has a mass of 1188 grams. The two spheres have a total mass of 132 grams. This makes the total system mass of 1320 grams. So the spheres are about 1/10th of the total mass.

Now we have the 10 to one ratio mentioned by Q. And lets start with one meter per second arc velocity just before the released of the cylinder and spheres.

Upon release: the spheres soon have the cylinder stopped; and then soon after the stop the spheres have the cylinder fully restarted. This is four frames at the start and four frame at the finish; as stated many times (1.2 m/sec). But lets stay with 1 m/sec just to simplify the math.

If energy is conserved when the spheres have all the motion then they are only moving 3.16 m/sec; if Newtonian momentum is conserved then the spheres will have to be moving 10 m/sec.

Now if energy is conserved there is only 31.6% of the Newtonian momentum remaining for the return of all the motion back to the cylinder. Collisions prove that only Newtonian momentum is conserved when small masses share their motion with larger masses.

This cylinder and spheres returns all the motion to the cylinders; just like all the scores of other cylinder and spheres do. This is a 10 to one mass ratio and I think I will stay with this model for a while.

Telecom; you are correct about Newton and his third Law. The force in the tether is equal to itself and the force is in both directions. So the momentum lost by the cylinder is gained by the spheres. And then when the spheres share the momentum back with the cylinder they have the adequate amount. The spheres can't be short (only 31.6%) of motion because all of the motion is restored back to the cylinder.

In this cylinder and spheres: 90% of the original motion belongs to the cylinder; because it has the same speed and 9 times the mass. For simplicity I let the speed be 1 m/sec around the arc of the circle.

If energy were to be conserved as suggested then 90% of the motion becomes 21.6% of the motion. This is because the spheres start with 10% of the motion; and only 21.6%  is needed to achieve 31.6%.  If the spheres have only 31.6% of the motion, when the cylinder is stopped, then 90% has become 21.6%. Confusing math to say the least. Nine units of motion are lost by the cylinder and only 2.16 units of motion are gained by the spheres.

F = ma on the other hand is most precise math. With F = ma 9 units of mass decelerates  from 1 m/sec to zero; while 1 unit of mass accelerates from 1 m/sec to 10 m/sec.  This is an equal quantity of momentum change on both ends of the tether; Newton's third Law.

There is not any experimental evidence for dropping Newtonian physic; but the abolition of Newton has certainly occurred.

[Low-Q]

OK. Do a simple experiment. The earth and a 2 gram steel ball.
Drop the steel ball to a hard surface and see what happens. The earth is much heavier than the steel ball, but momentum is still valid and conserved. If your theory is correct, the steel ball will bounce off the surface in a velocity greater than the speed of light.
If it does, you have a problem :-)


Vidar

[Delburt Phend]

This is the cylinder and spheres with a total mass of 1320g; and the spheres have a mass of 132g.

In the photo the cylinder is stopped and the spheres contain all the motion.

About a 1/12th of a second prior to the photo the motion was shared between the spheres and the cylinder. (four frames to cross 20 mm)

About a 1/12th of a second after the photo the rotational motion of the cylinder will be completely restored. (four frames to cross 20 mm)

If the spheres had conserved energy when they had all the motion it would take 12.65 frames to cross the 20 mm after the motion is restored to the cylinder.

The photo is at the high point of the energy;1000% of the original energy.

[telecom]

OK. Do a simple experiment. The earth and a 2 gram steel ball.
Drop the steel ball to a hard surface and see what happens. The earth is much heavier than the steel ball, but momentum is still valid and conserved. If your theory is correct, the steel ball will bounce off the surface in a velocity greater than the speed of light.
If it does, you have a problem :-)


Vidar

Vector of speed of the earth is 0 in the direction of the momentum of the ball.

[Delburt Phend]

Correct telecom; the only momentum in Q's system is from the 2 grams. In relationship to the 2 grams the earth is at rest. The spinning motion of the cylinder is transferred to the spheres and then back again; but the earth does not do that.