re: energy producing experiments

[Delburt Phend]

I would say that the ballistic pendulum is a solid fact; and that only linear Newtonian momentum is conserved when a small object gives its motion to a larger object. 

I would also say that, in several of these experiments, there is a complete restoration of the motion to the cylinder and spheres combination. If half of the experiment conserved linear Newtonian momentum then so also does the other half of the experiment. The same motion is maintained throughout.

The current experiment (a gravitational energy source) shows that these experiments are not condemned to avoid speed. High speeds a obtained easily; so much so, that some experiments are to be avoided. 

[broli]

You haven't answered the question at all, in fact you are encouraging me to not even experiment which is hilarious. Again I ask you, what is the measured final velocity of the sphere, what is the height difference of the dropped tube from where it's dropped to where it comes to a halt? If you do not have these numbers how can you make any statement about energy gain/loss?

[broli]

Let's see I used your latest video and did some calculations from what I can roughly deduce from the video. It was interesting to see that even with the rough estimates the input energy is pretty much equal to the output energy. According to your statements the sphere has to be moving at much greater velocities for your theory to hold.

[Delburt Phend]

I think you have calculated the average speed not the top speed.

As far as claiming the production of energy I will sight Issac Newton. When Newtonian momentum is conserved there is a massive increase in energy.
 
Please consider that someone (Newton, or Leibnitz, or a faulty use of Kepler) has to be right and someone else has to be wrong. There is going to be only one velocity. There are two or three equations under consideration and the same number will not satisfy more than one of these equations.  The three formulas are mv for Newtonian momentum: ½ mv² for kinetic energy: and mvr for angular momentum.
 
The Dawn Mission is a big throwing device so let's use it; it is about a 400 to one ratio.

So: We have a 400 kilogram (399 kg cylinder + 1kg spheres) thin walled hollow cylinder. The cylinder is spinning in space with an arc velocity of 1 m/sec around the arc of the circle.  It can be stopped by two .5 kilogram spheres.

When the cylinder is stopped: what is the arc velocity of the spheres?

The choices are 400 m/sec. for mv;     20 m/sec. for 1/2mv²;     or 16 m/sec. for mvr.

There is the concept of verification; but there is also the concept of elimination. How close do we have to be to 400 to eliminate 20? This is not the introduction of a new concept that needs verification: it is picking which one of the three hundred year old concepts is actually applicable to the experiment.

I have experiments that consistently fell within a 5% error range. In one experiment I would make four runs to get four data points: of the four data points two were sometimes the same thousandth of a second (i.e. .643, .642, .640, .642.) But I would not risk my photo gates on a sphere that is a blur. I do not have the capacity to measure blurs. And this brings us back to 400, 20, and 16.

If in the Dawn Mission experiment we got 30 m/sec would you be content to eliminate 400 m/sec. But in the same way if you got 270 m/sec would you be happy to eliminate 20 m/sec and 16 m/sec? 

I know for a fact that the two .5 kilograms spheres can return all the motion back to the 399 kilogram cylinder. You simply leave the spheres attached and all the motion returns to the cylinder. You can not do that with 20 units of momentum. It will take 400. 

[Delburt Phend]

Lets use Broli's chart to see how much momentum he has lost.

The drop is .5 meters. That is a final velocity of 3.13 m/sec.   The square root of (.5 m  * 2 * 9.81 m/sec/sec)

This gives us an input momentum of 2.7 kg * 3.13 m/sec = 8.451 units

Broli's chart has the final velocity of the sphere (.066 kg) at 20.56 m/sec.

That will give us a output momentum of 20.56 * .066 = 1.35 units.

That will give us 8.45 – 1.35 = 7.1 units of lost momentum.

Which means that 7.1 / 8.45 = 84% of the momentum is lost.

You can't possibly lose this much momentum. The Law of Conservation of Momentum (Newton's Three Laws of Motion) is the only motion law that actually stands up under real physical experiments.

I think these experiments can be conducted with only 5% loss of momentum; which gives you massive increases in energy.