Dr Ronald Stiffler SEC technology

[gyulasun]

Hi Lidmotor,
You asked in your above post:  "The question is how much power was pumping out of that one wire. "
It is difficult to measure, perhaps with a non inductive precision resistor which inserted in series with the single wire output that then is connected to the 22 uH choke and measure the voltage drop across it by a 2 channel scope with differential measurement technics...  which means the scope probes ground clips are left unconnected and floating and two pins of the two probes are connected to the two legs of the resistor. 
Perhaps a simpler method would be to use a load resistor across the + and -  outputs of the AV plug, also filtered with a puffer capacitor in parallel with it and measure the DC voltage across the resistor, then calculate the DC power. 

I took a snapshot from your video and edited a little to show the a possible measurements of the input DC power to the oscillator.  Unfortunately, the crystal oscillator you use has its own efficiency number, usually it is not specified and the internal circuitry may not be known to have a chance for estimating it.  Normally the usual oscillator circuit types has widely varying efficiency numbers, anything from say 40% to 70%. (Exception can be the so called Class-E type oscillators with over 85-90% efficiency).
With inserting a DC ampermeter into the positive input rail, the effect of connecting or diconnecting the AV plug or say varying the 22 uH choke coil inductance etc could be obseved. The R load resistance could be a few kOhm as a start.
If I may chime in to you, that is. 
Gyula

[Lidmotor]

Thanks Gyula,

   That info really helps.  I tried to find my old 13 MHZ crystal oscillator but it is lost somewhere.  I ordered some more but I think I might just build up your simple one transistor 13.4MHz crystal circuit and try that instead. That should get the job done  Your input here was of great help. Thanks again.

--Rusty
 

[AlienGrey]

Thanks Gyula,

   That info really helps.  I tried to find my old 13 MHZ crystal oscillator but it is lost somewhere.  I ordered some more but I think I might just build up your simple one transistor 13.4MHz crystal circuit and try that instead. That should get the job done  Your input here was of great help. Thanks again.

--Rusty

Mr Lidmotor, Hi there I don't suppose there is any hope you have a 27mhz xtal or any chance you can try the circuit at 13.5 mhz or 27mhz just a thought ?
I should be getting a 13.5 HC module in a day or two my self but dont have a 1mhz to try it against, will let you all know how it goes when i do.

regards AG

[mikrovolt]

The scope shows two different frequencies and amplitudes. The spec analyzer should show 4 side bands.
The addition of a coil loop forms standing waves for an auxiliary light source. Then there are harmonics.

[NickZ]

   Guys:
   Ok, so I took my Kacher's secondary coil (Tesla Coil) and disconnected it from everything, so it's just by itself now.
As I had heard the comment that I was turning this thread into something else.  When I haven't even started, yet.
   
   So, I then connected one end of the Tesla coil to my 2MHz signal generator, the other end of the TC coil to an AV plug, ending the plug with an small simple led bulb.
   So, what do you think happened?  Well, it would not light.  However, by tuning the frequency to around 1.5MHz, and adding a clip lead to one side of the plug, the led fires up.  Only at that frequency though.
  So, my SG does work to light an led, on a single wire test.
    I'll show a little video of that, later on today. As what it's showing was a little surprising, at least to me.
And I think that Slider, with get a kick out of it, for sure.
   
    So, Gyula, I think that I'm ready to continue with some more tests on the Doc's loop, and standing waves, etz...    I just don't know which one of his tests to go for.
    Any suggestions...
    As you know, I'm more interested in finding the anomaly, than just to light some bulbs, using just a tiny bit of power.
 
    If the Doc is listening, please join us, here. As we could easily stray off course, without your help.