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Overunity Machines Forum



Confirmation of OU devices and claims

Started by tinman, November 10, 2017, 10:53:19 AM

Previous topic - Next topic

0 Members and 8 Guests are viewing this topic.

lancaIV

https://www.google.com/search?q=ne-2+lamp+voltage&ie=utf-8&oe=utf-8&client=firefox-b-m
NE-2 : VDC 90 Design current 0,3 mA ( Farnell data)

                                                               
                                                         ergo starter input power                                                                 

                                                                         0,027 VA

                                          with Voltage drop down to average 0,02 VA input

                                                 benfr, this is the energetic demonstration level !
( Without calculating and measurement from peak and average inrush voltage and/ or inrush current)


gyulasun

Hi Bastien,
Sorry but I already wrote to you (but you disregard it  :P ) that there have been several other people who operate neon lamps from very low input voltages, why should I build such circuit you refer to when it needs a function generator etc? 
Here I quote from my earlier post on circuits you can also build and get rid of the use of a generator:

"a neon bulb like you use (NE-2 type) does not need an expensive kit to make it light up, 
just build a Joule thief oscillator and take say an 1.2 volt battery and the bulb will be lit nicely with them.
Here is a 4 minute long video showing it in action: 
https://www.youtube.com/watch?v=9MxIXESkS3I

The circuit can work from even a discharged battery that has about 0.84 VDC only and you can see input voltage amplified
up well over 100 volts shown on the oscilloscope.
Here is another Joule thief for operating a neon bulb:
https://www.instructables.com/id/high-voltage-joule-thief/ 

If you have some more time, this video includes several Joule thiefs including neon bulb: 
https://www.youtube.com/watch?v=fQqAP_tyEqg  "         

In fact, the oscillator circuits (known among the tinkerers as Joule thiefs) substitute your signal generator and they use much less input power.   

Gyula

benfr



Quote from: gyulasun on April 30, 2019, 08:13:06 AM

Sorry but I already wrote to you ()but you disregard it) that there have been several other people who operate neon lamps from very low input voltages, why should I build such circuit you refer to when it needs a function generator etc? 
Here I quote from my earlier post on circuits you can also build and get rid of the use of a generator:

ok, Guyla, I think I understand your point. Your examples are fine, I didn't know them. Thanks for letting me know. They could be very useful for me also.
I understand you do not have a freq gen, hence...
So to answer you...it is not a problem to substitute another load instead of the NE2 : I can check what I have and you'll have to wait if I don't.
I have, though, experienced the same amplification with 4 V LEDs with a 1 V input .
We can think of any other load ; if you have suggestions, please offer them.


Quote from: lancaIV on April 30, 2019, 08:12:58 AM
https://www.google.com/search?q=ne-2+lamp+voltage&ie=utf-8&oe=utf-8&client=firefox-b-m
NE-2 : VDC 90 Design current 0,3 mA ( Farnell data)   ergo starter input power                                                                 0,027 VA
   with Voltage drop down to average 0,02 VA input

benfr, this is the energetic demonstration level !

thanks for taking a look !
one step at a time Sir. here I have not stated yet that the whole machine including the freq gen is OU... yet. That's what I'm showing for the circuit inside although you may reproach me not to have yet measured amperage there. Don't worry for that now, if you're kind and patient, God will provide for your wildest dreams right here on this forum. :p

lancaIV

benfr,you do not need to state but has to follow the NE-2 industrial numbers as fact :

at start 0,027 later 0,02  Volt-Ampere DC under full load condition
the Neon lamp  consumes for measureable stable  lumen output.

With 50 Neon lamps  NE-2 connected under full load condition this gives 1 Volt-Ampere per hour or ~ 1 Wh load charge need.
                                                                   
                                                                            DC versus( pulsedDC) AC :


                               AC less Voltage need, Amperage  with AC ? With pulsed DC = modified AC ?

                                                                             With feedback cycle ?

                                                                 lumen output power recuperation ?

itsu

Quote from: gyulasun on April 28, 2019, 08:56:07 AM
Hi a.king21,

Would like to ask you whether you are aware of the received power levels quantitatively at the output of each receiver module? LED lamps (say with 3 to 5 W data sheet ratings) are surely lit but actually how much power drives them is not shown as measured, this is why I ask.

It is ok that performing such measurements is not easy (instruments are in the vicinity of the strong EM near field of the single transmitter coil). Perhaps Using a full wave diode bridge across the AC output of each receiver modul and say the use of 100 or 220 uF puffer capacitors to filter the diode's DC output would help: this DC output then could drive a known resistor load across which just a DC voltage level check would be needed. 
The value of these resistors could be calculated like this: if the shown LED lamps were say 12V and say 3W rated, then their equivalent resistance were (12 x 12) / 3 = 48 Ohm, ok? (use a 47 Ohm, at least 2W rated ones). This is the load any such LED lamp (12V, 3W) would represent towards any 12V voltage source when the source is able to maintain the 12V voltage level.  For other LED lamps the same calculation can be used to learn what actual load they represent when fed by their specified voltage.

Obviously, if the voltage level is say 11V or 9.5V or less, the consumed power by this LED becomes less and less too, LED lamps are non linear loads. However, the actual DC power dissipated in a resistor can immediately be known by a simple DC level test across the resistor. If you find say only 10V across a 47 Ohm resistor, then the consumed power would be (10x10)/47=2.1W and so on.  Notice that a 2V less input voltage (wrt 12V) results in almost 1W less power draw.

For diode bridges,  the cheap UF4007 fast Si diodes are fine, especially if each diode in the bridge is made of two paralleled ones, to reduce overall voltage drop across the bridges.Or use Shottky diodes to make the bridges to reduce voltage loss further on.

This way, by summing up the DC power levels in the resistors across each receiver output, and checking the DC input to the transmitter coil driver IC, a fair comparison of the input and output powers can be obtained. 
Are you aware of any such tests done on a single transmitter, multiple receiver modul setup?

Could you do such tests if you have such kit? This is the only way to arrive at any performance evaluation.
If truth is important, that is.
I am not trying to nit-pick with you or anyone else, even a 'mere' COP = 1.5 result would be fantastic, not to mention anything higher, like a COP 144 claim. Do you agree?

Thanks, Gyula

Gyula,

concerning your writing in this post above, what would be the preferred setup for the coils, vertical like in the
below picture or horizontal which i understand from Rick's video?

Planning to drive the center coil (transmitter coil) directly from my FG (initially) with a 47pF series cap. and
the 5 receiver coils each with a 100pF series trimmer cap. to the by you suggested FWBR, 220uF puffer cap and a good known resistor.


Itsu