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Overunity Machines Forum



Negative Inductance and measure of Magnetic force.

Started by synchro1, November 19, 2017, 08:20:57 AM

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synchro1


I want to thank everyone who's been keeping up with my comments and watching my videos. Especially member Gotoluc, who clued me in to the value of the high inductance choke off his "Self running coil" thread. My latest test proves he's been right the entire time.

I connected the coil electrodes from each EM to the DMM set on both the A.C. and D.C. volts scale and stabbed at them with the flat side of a ceramic block magnet, and got a huge difference in voltage output, in proportion to the difference in inductance. The consequences are awesome!

The 10 Henry choke is generating over 10 times the output! The high perm EM can oscillate a much larger piston magnet for the same input as the round EM, so just ball parking for now, the high perm EM attraction oscillator with the SPDT switch should be at least 100 times over unity. This is really dynamite!

There's really not any further to go with the project, it's perfected.

Captain Midnight Rollover from the "Black Friday Project".

truesearch

@synchro1


Can you post a diagram image outlining what you are doing ? I'm not really following what you have described . .  :(


truesearch


synchro1

Quote from: truesearch on June 21, 2018, 10:14:04 AM
@synchro1


Can you post a diagram image outlining what you are doing ? I'm not really following what you have described . .  :(


truesearch

@truesearch,

Let me ask you a question first; You understand how wrapping an iron nail will increase the magnetic attraction strength of a coil of wire independently of input, right? The same nail will increase the electrical output of the coil, in the same proportion, from the motion of a permanent magnet. I need to know if you follow what I just stated before I can help you with a diagram.

The coil wrapped nail has an axial polarity. Now imagine we position a permanent magnet with it's magnetic polarity in opposition to the electromagnetic pole, that's attracted to the ferrite in the nail. So, the magnet's stuck on the nail head, until the coil that's wrapped around it is energized. That magnetic pulse then repels the permanent magnet, right? When the power pulse stops the magnetic attraction of the permanent magnet to the nail generates a current in the coil as it's attracted back.

It would return the power to source if we didn't wire a separate pathway to storage through the SPDT switch.

Naturally, this is an oversimplification and involves the B-H curve in actual practice.

truesearch

@synchro1


That does make sense the way you've described. Thanks!

A question: wouldn't it take more electrical "energy" to power the electro-magnetic coil that has a permanent magnet with it's magnetic polarity in opposition to the electromagnetic pole? I'm just supposing that whatever "gain" is captured would be in comparison to the additional energy input. . .  :-\


truesearch

synchro1

Quote from: truesearch on June 21, 2018, 02:01:52 PM
@synchro1


That does make sense the way you've described. Thanks!

A question: wouldn't it take more electrical "energy" to power the electro-magnetic coil that has a permanent magnet with it's magnetic polarity in opposition to the electromagnetic pole? I'm just supposing that whatever "gain" is captured would be in comparison to the additional energy input. . .  :-\


truesearch

@truesearch,

That's really a very good question. Let me ask you this: Does a flashlight draw more power when it shines it's light against a wall then when it shines into free space?

This video by Woopyjump shows that there's no difference in input with or without the magnet pendulum in front of the pulse coil:

https://www.youtube.com/watch?v=vLiUkno3tSY&t=7s