The secret to Overunity

[sm0ky2]

I have tamed the static.

Some of it anyway.   

http://www.youtube.com/watch?v=f-aP7sk48jw

Nice
So the ball rides the cone of the cup like a belt-transmission?
Larger radius = higher up the cup it goes?

[sm0ky2]

You are right if you are talking about a closed circuit. The total energy should be from the source if the environment factor remains normal.

The environmental factor (in most conditions) is relatively infinite.
We live in a sea of electrons and positrons
Even the parts of the machines themselves become entangled in the process.


If you wanted to get technical, the 'source' is the environment
The static machine simply provides a mechanism for transfer.
99% of the energy we use to initiate the charge differential
Can be attributed to friction. And has nothing to do with the process.
If a good insulator is used, there is no "cling", and the action of separation
Has no opposing force.


In a rotary machine, rotational momentum dominates.
The faster the rotation, the higher the voltage
But the flywheels are easier to turn in this condition.


Our modern generators become harder to turn at full production
This is because our brute force methodology holds one half still while
forcing the other like a pump.


I think in order to reduce the greater part of our energy losses
(the portion of energy that is lost to heat and magnetism in our devices)
We need to create technology that uses both electrical forces.


The field equations are exactly the same, you simply change the sign of the charges.


Consider the dual-plate condenser, and notice how the secondary plates were connected
they form an independent circuit, each side has the opposite charge of each jar
And a transitional current develops to keep the charges balanced to a 'middle voltage'
if we think of this now as our "ground", we can begin to think about the type of technology
we should be designing. (butterfly/leaf/mirror image?)

[Tajerek]

Would be nice if it so easy, but u are wrong.

Formula 4) The time taken to fully charge a cap from a voltage source is 5*R*C

Yes, formula is true but in your schematics R is very low like a short circuit. So I=U/R, that means a huge amount of current.....

That's Ok it means it charges faster. Then once the Cap is charged it acts like an open circuit to DC. You HV module shouldn't have a short circuit breaker.

[Tajerek]

The charge TIME is to be consider for the power transfer..  Look at scopes shot of a disruptive high voltage trough a spark gap and the RAISING TIME occupy most of the screen..  The relation between the L1 and L2 is directly related to raise and surge of L1 because L2 has it`s capacitance and is acting 180 degree trough the curent cycle... This will give the L2 a more sinusoidal wave given a full amplitude.

You lower the charge time by increasing the voltage (even way beyond the rating of the cap) and reducing the R. this means you have to pick low ESR cap. I won't go into the formulas and calculations to prove it but you can test and see.

You will probably ask how come I raise voltage way beyond the rating of my cap ? won't that bend the plates of the cap and it fries and becomes a deadshort ?! well No as long as you are discharging it as soon as it fills up. That's what the spark gap does.

[Void]

You lower the charge time by increasing the voltage (even way beyond the rating of the cap) and reducing the R. this means you have to pick low ESR cap. I won't go into the formulas and calculations to prove it but you can test and see.

Hi Tejerek. Again, lowering the charge time will not in any way bypass the energy consumption
from the input power source required to charge up a given capacitor to a given voltage. This has
already been pointed out to you.

Rather than suggesting other people test your false assumptions for you, why not do some
basic testing with capacitors yourself and you should quickly see where you are going wrong in your assumptions.
It will not work as you say. This thread should more appropriately be called 'The secret to self-deception'.
Sorry, but for someone to claim to know how to achieve OU when they obviously haven't even done the most basic
testing of their assumptions is silly.

All the best...