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DESTROYING Energy

Started by EHT, January 28, 2018, 03:06:03 PM

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EHT

Quote from: gravityblock on February 02, 2018, 07:18:50 PM
Let me simplify this for you and the others, since my word experiment is somewhat confusing.

A good example in how COM (Conservation Of Mass) holds while COE (Conservation of Energy) is violated can be seen in transferring the momentum of a heavier mass to a lighter mass, according to KE = 0.5 * mv2.  It's known by top physicists that Newton's zeroth law is invalid.

A 5 kg mass moving 1 m/s has 5 units of momentum and has a kinetic energy of 2.5J.  A 1 kg mass moving 5 m/s has 5 units of momentum and has a kinetic energy of 12.5J

12.5J > 2.5J !!!  <------ Conservation of energy is violated when transferring the momentum of a heavier mass to a lighter mass, while the 5 units of momentum is conserved!

Gravock

The confusion here is that momentum is not a conserved quantity in this example. Momentum is mass x velocity and NOT the same as energy. You cannot transfer momentum and expect the same energy because they have different equations.

IF a 100% transfer of energy between the masses were to be effected, then it would result in the 1kg mass having a velocity of sqrt(5) m/sec - approx 2.236 m/sec

Mass 1kg. Energy=2.5J

V=sqrt(2E/m)
=sqrt(2 x 2.5/1)
=sqrt(5)
=2.236 m/sec

E=(mv*2)/2
= 1 x sqrt(5)^2/2
=5/2
=2.5J

Ask any "top physicist" (or just a "normal" physicist, for that matter) and they will tell you the same.



gravityblock

Quote from: EHT on February 03, 2018, 12:25:42 AM
The confusion here is that momentum is not a conserved quantity in this example. Momentum is mass x velocity and NOT the same as energy. You cannot transfer momentum and expect the same energy because they have different equations.

IF a 100% transfer of energy between the masses were to be effected, then it would result in the 1kg mass having a velocity of sqrt(5) m/sec - approx 2.236 m/sec

Mass 1kg. Energy=2.5J

V=sqrt(2E/m)
=sqrt(2 x 2.5/1)
=sqrt(5)
=2.236 m/sec

E=(mv*2)/2
= 1 x sqrt(5)^2/2
=5/2
=2.5J

Ask any "top physicist" (or just a "normal" physicist, for that matter) and they will tell you the same.

Where did I transfer momentum and received the same energy in my example as you have falsely asserted?  Where did I use the same equation for both the momentum and energy in my example as you have falsely asserted?  I used mass x velocity for momentum and 0.5 * mv2 for the kinetic energy!

5 kg mass moving 1 m/s = 5 units of momentum (mass x velocity).  <-------  KE = 2.5J (KE = 0.5 * mv2)
1 kg mass moving 5 m/s = 5 units of momentum (mass x velocity)   <-.------  KE = 12.5J (KE = 0.5 * mv2

As you can clearly see, momentum is a conserved quantity in my example, which you falsely asserted was not a conserved quantity in my example!  Also, energy is not a conserved quantity in my example, which you falsely asserted that it is a conserved quantity in my example.

2.5J is not the same energy as 12.5J!  I never transferred momentum and expected the same energy in my example because I used different equations for the momentum and energy.

You're clearly trying to mislead the reader!

Gravock
Insanity is doing the same thing over and over again, and expecting a different result.

God will confuse the wise with the simplest things of this world.  He will catch the wise in their own craftiness.

gravityblock

Quote from: gravityblock on February 03, 2018, 01:28:29 AM
Where did I transfer momentum and received the same energy in my example as you have falsely asserted?  Where did I use the same equations for both the momentum and energy in my example as you have falsely asserted?  I used mass x velocity for momentum and 0.5 * mv2 for the kinetic energy!

5 kg mass moving 1 m/s = 5 units of momentum (mass x velocity).  <-------  KE = 2.5J (KE = 0.5 * mv2)
1 kg mass moving 5 m/s = 5 units of momentum (mass x velocity)   <-.------  KE = 12.5J (KE = 0.5 * mv2

As you can see, momentum is a conserved quantity in my example, which you falsely asserted was not a conserved quantity in my example!

2.5J is not the same energy as 12.5J!  I never transferred momentum and expected the same energy in my example because I used different equations for the momentum and energy.

You're clearly trying to mislead the reader!

Gravock

Four false assertions by EHT in a single post!  This is an interesting pattern developing from EHT...ROFLMAO!!!!

Gravock
Insanity is doing the same thing over and over again, and expecting a different result.

God will confuse the wise with the simplest things of this world.  He will catch the wise in their own craftiness.

gravityblock

Quote from: gravityblock on February 03, 2018, 01:39:02 AM
Four false assertions by EHT in a single post!  This is an interesting pattern developing from EHT...ROFLMAO!!!!

Gravock

....and EHT falls flat on his face like the Double Domino Effect (wait for it)!  Additional angle of the Reverse Domino Effect.

Gravock
Insanity is doing the same thing over and over again, and expecting a different result.

God will confuse the wise with the simplest things of this world.  He will catch the wise in their own craftiness.

EHT

Quote from: gravityblock on February 03, 2018, 01:28:29 AM
You're clearly trying to mislead the reader!
Gravock

I'd bet that the readers here are not as easily misled as you seem to think.