12 times more output than input, dual mechanical oscillation system !

[Nabo00o]

Thank you Merg, I'm reading that paper right now and its getting really interesting!
Also, the parametric oscillator seems to link another generator I thought of making with the 2-stage one, it uses a varying capacitance where a rotor with special plates passes through 2 or more parallel connected capacitors, alternating their C and V values and thus makes a current go back and forth between them. The thing is that the plates are first dragged in by the caps but must then be dragged out again, resulting to a net zero work done. But the capacitors do still circulate current....

Science is interesting
Julian

[Merg]

Thank you Merg, I'm reading that paper right now and its getting really interesting!

So, what do you say about this paper?

[onthecuttingedge2005]

It is just a transfer of leverage, the stored amount of energy remains the same as any other type of stored energy, it gets depleted.

Don't be fooled by the illusion of leverage as being OU.

I could move an entire mountain of weight with a simple but tiny clock motor and a great deal of leverage but it would take me a very very long time to move it.

You could however move a super large magnet through an induction coil with very little effort with just a slight amount of force if you use enough leverage but you would have to remember you are sacrificing speed over length on the lever. if you can find an enormously powerful field magnet then the small amount of movement in the coil might be enough to generate more electrical potential than what is used on the long end of the stick.

no promises on that.

Jerry

[Charlie_V]

It is just a transfer of leverage, the stored amount of energy remains the same as any other type of stored energy, it gets depleted.

Actually, it is not just the transfer of leverage.  It appears this way because he is using a lever.  If you keep the pendulum's pivot point stationary, there is no damping other than friction of the pendulum. 

The main point I see in this device (even if implemented wrong) is that you are RE-using energy stored in the pendulum. Assuming the pivot point does not move, the initial energy placed into the pendulum does not leave the system.  Friction produces energy "radiation" so that you must maintain a small input of energy to stop the pendulum from swinging down. 

Now lets say you alter Milkovic's design so that the pivot point does not move.  Gravity will try to take the stored energy in the pendulum and change the frequency of the pendulum across its period.  So that starting from a 90 degree position (90 degrees from the rest position) and moving to the 0 degree position (0 degrees being the rest position), the frequency of the pendulum will shift from high to low.  From 0 degrees back to 90, the frequency shifts from low to high.  This happens at twice the frequency of the pendulum, so that the system functions as a parametric oscillator.  The only energy being lost here is friction.  Placing a load properly on the altered Milkovic design will only stop the pendulum's frequency shift, allowing the pendulum to swing at a constant frequency equal to the frequency at the 90 degree position.  The average amount of energy required to keep the pendulum swinging is the same whether the device is loaded or not. 

From the standpoint of energy input/output, it should take less input than the output because if you ignore the initial input to lift the pendulum to the 90 degree height, the energy to keep it swinging is much less.  Since the pendulum is not damped from the loading, it may be possible to feed the energy back to keep the pendulum swinging.

You could however move a super large magnet through an induction coil with very little effort with just a slight amount of force if you use enough leverage but you would have to remember you are sacrificing speed over length on the lever. if you can find an enormously powerful field magnet then the small amount of movement in the coil might be enough to generate more electrical potential than what is used on the long end of the stick.

This will not work because the leverage is directly effected by the counter force produced when the coil is loaded.  So it will become harder to push the magnet through the coil.  In effect, the lever system is damped, regardless of leverage. 

In the Milkovic example, the pendulum is not damped by the load, and so it can be fed back.  Unfortunately, Milkovic's device is not properly designed so it will not be able to function in this way.  We have to alter it!

[FreeEnergy]

Charlie_V
nice explanation!