12 times more output than input, dual mechanical oscillation system !

[pilatte]

When Milkovic's device is at rest, should the torque on the side of the pivot opposite the pendulum be greater or equal to the torque on the side with the pendulum? In other words when at rest should the device naturally lean towards the side opposite the pendulum or should the lever be balanced.

Hi vladimir,
I test several devices similar of milkovic's device.
but when I try to extract mechanical energy from the opposite side of the pendulum : there was a stop of the device (the balancing effect stops).
for more details, see my post "Pilatte reply #378 march 31 with drawings of my last device.
please, give me your opinion on what's wrong with that concept.
thanks
Pilatte

[i_ron]

When Milkovic's device is at rest, should the torque on the side of the pivot opposite the pendulum be greater or equal to the torque on the side with the pendulum? In other words when at rest should the device naturally lean towards the side opposite the pendulum or should the lever be balanced.

Vladimir,

It can be either. If you start with a perfectly balanced secondary beam then the
output strokes will be somewhat equally matched.

If you bias the beam to one side then the torque is not evenly split and one side
of the stroke will be stronger than the other. A good example is the "hammer"
machine where more power is diverted to the hammer stroke.

Ron

[Vladimir256]

It can be either. If you start with a perfectly balanced secondary beam then the
output strokes will be somewhat equally matched.

If you bias the beam to one side then the torque is not evenly split and one side
of the stroke will be stronger than the other. A good example is the "hammer"
machine where more power is diverted to the hammer stroke.

Thank you for your response. So you are saying that a better output will be achieved if the torque is greater on the output side of the beam?

Also, one possible way to test this device is to hold the beam stationary, raise the pendulum to a certain height, and measure how long it takes for the pendulum to come to a stop. Then compare that time with the time it takes to stop if the beam is free to move.

[i_ron]

It can be either. If you start with a perfectly balanced secondary beam then the
output strokes will be somewhat equally matched.

If you bias the beam to one side then the torque is not evenly split and one side
of the stroke will be stronger than the other. A good example is the "hammer"
machine where more power is diverted to the hammer stroke.

Thank you for your response. So you are saying that a better output will be achieved if the torque is greater on the output side of the beam?

Also, one possible way to test this device is to hold the beam stationary, raise the pendulum to a certain height, and measure how long it takes for the pendulum to come to a stop. Then compare that time with the time it takes to stop if the beam is free to move.

Vladimir,

What are you calling the "output side of the beam"? The beam has two strokes,
an up stroke and a down stroke, right? What I was saying was if you bias the
beam to be heavy to one side or the other then you affect the torque output
ratio of these two strokes.

What I found is if you let the beam flop up and down unimpeded it will kill the
pendulum. The beam must be doing work so as to restrict the beams motion.
With no load on the beam it will go into parasitic oscillations and play havoc
with the operation of the pendulum.

This is understandable when we remember le botafumeiro, where a group of men
provide input to the pendulum by raising the pendulum on the down swing!

So if we drop the pendulum on the down swing no good will come of it. But as
well it should be clearly understood that raising the pendulum on the down swing
is horrendously energy intensive. This is the worst case scenario for inputing
maintaining energy to the pendulum ...and this is your answer Pilatte. It will take all
or more of the secondary beam's energy to drive the pendulum from this input point.   

Ron

[Vladimir256]

What are you calling the "output side of the beam"? The beam has two strokes,
an up stroke and a down stroke, right? What I was saying was if you bias the
beam to be heavy to one side or the other then you affect the torque output
ratio of these two strokes.

By the output side I mean the longer side opposite the pendulum. Is the device more efficient if more weight is added to this side, or is that detrimental?

For those who are testing this device, remember: the potential energy input into the pendulum (in joules) is found by the formula mgh m=mass of pendulum (in kg) g=9.8 m/s h=height in meters that the center of mass of the pendulum is raised.

Although Milkovic's flashlight experiment was somewhat helpful, the part where he showed that the flashlight used for the input powered 9 others was unconvincing. He obviously input more energy then required to light the one flashlight on each stroke because his hand+the flashlight had kinetic energy when it struck the pendulum.