12 times more output than input, dual mechanical oscillation system !

[ltseung888]

The lead-out energy as applied to the seesaw when a "jumping" load is applied.

Let us assume a balanced seesaw with weight W1 at both ends.  The LHS has a weight W1.  The RHS has an unbalanced wheel with unbalanced weight W2 at the rim and weight W3 of the wheel.  W2 plus W3 equals W1.  No gravitational energy will be lead-out in steady or no motion state.

With the unbalanced wheel at the RHS rotating, the force exerted downwards will vary with the centrifugal force.  It can be compared with a person jumping up and down at the end of the seesaw or lever.

When the Weight W2 is at the top position (highest potential energy) and lowest kinetic energy (lowest velocity), the downward force will be lower than W1.  The Weight W1 on the LHS will do work against gravity to cause anti-clockwise rotation.  This energy "enters" the seesaw system.  When the Weight W2 is at the lowest position, the downward force will be higher than W1.  The Unbalanced Wheel will do work against gravity to cause clockwise rotation.  This energy "enters" the seesaw system.

Thus the "jumping" brings in potential energy equal to W2 x g x h where h is the total height moved by W2 in the seesaw view.

This is the more correct analysis of lead-out energy of the seesaw.  The Milkovic 2SO or Chan Wheel leads-out energy from pendulum motion and also from seesaw motion.

God Bless.  The Physics and Mathematics is now complete.  The Milkovic 2SO and the Chan Wheen are both lead-out energy devices.  Both lead-out gravitational energy.

Leading out magnetic and electromagnetic energy follows a similar path.

I shall discuss the arrangement of a pure magnet wheel such as the Wang Motor in the coming posts.  The Wang Wheel can lead-out magnetic energy by clever arrangement and shielding.  The Minota Wheel from Japan is similar.

[ltseung888]

So that would be W1xgxh for the output and then the input would be

(W2xgxh)+(W3xgxh)

With W3h being the start height from table to end height from table without the lever arm being allowed to move after lift of the output and without the wheel being allowed to spin backwards.

W2h would just be the distance from the table of the axle at start minus the distance from table at the end of the half cycle without the arm being able to move it back up. IOW how far down the wheel traveled.

You will notice that the W3 weight will move down a lot further and then back up some distance as the wheel continues to rotate but it will not make it back up to the start angle position of the wheel,, TDC of the wheel.

This drop from TDC plus the drop in wheel height will equal the drop in g of that weight.

This is the stuff I came up with when testing a very similar setup.  I used one way bearings to stop the reverse movements of both the wheel and the lever arm.

Dear Webby1,

Thank you for your analysis.  I was puzzled at the huge COP.  Now that the new comparison is:
Output = W1xgxh and
Input = (W2xgxh)+(W3xgxh)

That brings COP way down.  I shall repeat the experiments and see if COP is still greater than 1.  I believe it will still be greater than 1 because of the "jumping" at one end of the lever will lead-out or bring-in gravitational energy.

Any leading-out or bringing-in of gravitational energy will be a breakthrough.  It will open the doors to leading-out or bringing-in of magnetic or electromagnetic energy that can be thousands times more.

Keep the constructive comments coming...  We are all students with much to learn in this new field.

[Paul-R]

Any leading-out or bringing-in of gravitational energy will be a breakthrough.

Lawrence: You mention leading in and bringing out regularly but what is the precise definition of these terms and from where is the energy lead in or brought out?

[ltseung888]

Another video showing Chan Wheel lifting Weight W1 higher after first swing.

http://youtu.be/d4Bxnv3dewI

[ltseung888]

Lawrence: You mention leading in and bringing out regularly but what is the precise definition of these terms and from where is the energy lead in or brought out?

Paul-R:

In a traditional machine,
the Input energy X = the Output energy Z1 + energy loss Z2.
X = Z1 + Z2
Z1 = X – Z2 and thus the Output Z1 cannot be greater than X.

In the Lead-out or bring-in energy machine, additional energy Y comes from the environment.  One example discussed in the Milkovic 2SO is gravitational energy.  When you push a pendulum horizontally, the physics and mathematics show that the tension in the string increases.  The vertical component of the tension of the string lifts the bob.  This energy is NOT transferred from the user supplied horizontal energy.  This "non obvious" energy is referred to as the lead-out or bring-in energy.

In a lead-out energy machine
The user supplied energy X + Lead-out energy Y = Output energy Z1 + Loss Z2
X + Y = Z1 + Z2
Z1 = X + Y – Z2  Thus Z1 can be greater than X  if Y is greater than Z2.

If we just compare Z1 and X, we may fall into the trap of saying that
the Observed Output Energy Z1 is greater than the Observed Input Energy X.
There is a violation of the Law of Conservation of Energy.

The correct Input Energy is X + Y.  The Law of Conservation of Energy is obeyed!