Zero and Q device

[v8karlo]

   Karlo:   I am using a crystal oscillator which is connected to a "diode loop", pictured below.
   The diode loop allows for both positive and negative pulses from the oscillator to be utilized by the output.
The IN4148 diodes are switching diodes, and help to increase the voltage, similar to what your capacitors are doing. The two leds bulbs that are in the middle of the diode loop are 120v 8w AC bulbs, and can light fairly bright, although not as bright as when connected to the grid. Each diode added to the loop is increasing the output voltage. Each bulb is equivalent of a 60w incandescent bulb.
  Possibly the same type of diode loop and led bulbs can be used on your type of oscillator or device to allow both polarities (full sine wave) to be used, which may give a higher bulb brightness (lumin levels) than what incandescent bulbs will do on limited input sources.
   The oscillator, (or signal generator) is on the left side of the diagram, cap C1 and C2 help to separate the polarities from the source pulses, along with the series connected twin diode loops.
   If you have questions, just let me know.                                                             
                                                             

Your C1, C2 here are very interesting.
When you adding diodes you are adding resistance, so in C1, C2 will remain charges from that phase because of resistance, they will not empty all the way.

Whatever voltage remains in them from that phase,
in next phase they will be in serial connection with source raising (adding it's voltage to source voltage) the voltage on their line.

You are doing the same thing as CZero does, but with diodes.
Using serial connection of caps and source.

Maybe I am wrong, but it looks to me that is the case.
You can test it easily. Remove caps, if the voltage do not raise then that's it.
Just like in Zero, remove CZero, voltage is gone, and power.

OK, thanks for help!

[lancaIV]

What you are doing is not unknown,  it is the electro-magnetical device in :
https://de.m.wikipedia.org/wiki/Kernwaffe
the chain reaction starter, by compact impulse !
What is written under the first picture?
https://en.m.wikipedia.org/wiki/Cockcroft%E2%80%93Walton_generator
https://www.google.com/search?q=farnsworth+fusor&client=firefox-b&oq=farnsworth+fusor&gs_l=mobile-heirloom-serp.3...153299.156409.0.157160.6.6.0.0.0.0.0.0..0.0....0...1c..34.mobile-heirloom-serp..6.0.0.3iAUs2knNG0

PROLIFERATION ?
Messer,Gabel,Schere,Licht(?) : sind fuer " kleine Kinder " NICHT ALLOWED !

[v8karlo]

   The oscillator, (or signal generator) is on the left side of the diagram, cap C1 and C2 help to separate the polarities from the source pulses, along with the series connected twin diode loops.
   If you have questions, just let me know.                                                             
                                                             

This is very interesting circuit.

I didn't saw before that you separating polarities!

[Hoppy]

If the voltage on caps are doubled, then the power on that caps is doubled too (more than double actually).??
Capacitor of 100uF filled to 175V has more power than capacitor of 100uF 90V.

We are talking about power here. Time to accept that.

OK. Let try one last time.

Your statement is correct in that the 175V charged cap has more stored energy than the 90V charged cap. However, you need to understand that the increase voltage is not a free energy gain because it has been achieved by pulling additional energy from the power supply. A voltage doubler has to use both cycles of the AC supply to function. Whilst the caps 1 to 3 are discharging to L2, CZero is re-charging. You fail to show this on your current flow diagrams in your book. So, when the caps 1 to 3 are ready to re-charge from the supply, they also receive the additional peak voltage already stored in CZero from the previous cycle, thus the voltage doubling action. See this link for a full explanation on the operation of voltage doublers.

If you were to measure the input and output power correctly, you would find that although the current discharge from caps C1 to C3 is now just sufficient for L1 to glow, it is at the expense of a large voltage reduction measured across L1 in comparison with the combined peak voltage levels on C1 to C3.

[v8karlo]

OK. Let try one last time.

Your statement is correct in that the 175V charged cap has more stored energy than the 90V charged cap. However, you need to understand that the increase voltage is not a free energy gain because it has been achieved by pulling additional energy from the power supply. A voltage doubler has to use both cycles of the AC supply to function. Whilst the caps 1 to 3 are discharging to L2, CZero is re-charging. You fail to show this on your current flow diagrams in your book. So, when the caps 1 to 3 are ready to re-charge from the supply, they also receive the additional peak voltage already stored in CZero from the previous cycle, thus the voltage doubling action. See this link for a full explanation on the operation of voltage doublers.

If you were to measure the input and output power correctly, you would find that although the current discharge from caps C1 to C3 is now just sufficient for L1 to glow, it is at the expense of a large voltage reduction measured across L1 in comparison with the combined peak voltage levels on C1 to C3.

Ok, you are right.


Can you tell me did you made the input output  power measure?


I am asking you that because I am waiting for measurement results from few other people.