Zero and Q device

[Hoppy]

Ok, you are right.


Can you tell me did you made the input output  power measure?


I am asking you that because I am waiting for measurement results from few other people.

No, not on your specific circuit but I have measured power levels on other circuits using voltage doubling circuitry.

Please understand that I'm simply giving you the accepted understanding of how this type of circuitry functions within the conventions of electrical principles. I am not here to give you a set of test measurements and I'm not intending, after your harsh and disrespectful worded replies to me and others just trying to help you gain a better understanding, to post any further on this thread. Its up to you whether you still continue to believe that your circuit is amplifying power.

Best wishes.

[v8karlo]

I just received measurements of J circuit.
Load is 10ohm.

You helped Hoopy. Thanks. It is reasonable that you don't have to measure anything.
I respect your view.

[NickZ]

   Looks like the feed back circuit is returning less than 100mA to the 12v battery. Which would not keep the battery up for very long, if a 25w bulb or bigger bulb were used as the load.
   But, there is no actual output readings, at the bulb, to compare with the input current.
   Karlo: here is a link to the "double diode loop" by Dr. Stiffler.
   https://youtu.be/8VRqf8E8VIM
   I also have some videos about that circuit, or at least my versions of the Docs device, if interested.
   You can look on youtube,  just search for my name, Nick Zec.
   Or for my youtube channel.   Here is my last video about the diode loop.: https://youtu.be/BZsvtlA_Rgc

[lancaIV]

1 circuit,  cycle 90% peak efficiency :
------------------------------------------
1 . cycle 100% in    90% out

2 . cycle   90% in    81% out

3 . cycle   81% in    73% out

..   cycle.   .  % in.  +-0% out

COMBINED "TOTAL WORK CYCLES " OUTPUT ( 90% + 81% + ...... ) FROM THE BEGINNINGS "100%" !?
                                                     result/ numbers of cycles : average efficiency
                            peak cycle efficiency : average cycle efficiency : coefficient of work performance
.................
https://www.researchgate.net/publication/306121298_Mandelstam-Papalexi-Bethenod_Generator_a_Parametric_Dynamo
different research view and kinds and modi about :
https://www.google.com/search?q=parametric+generator+papalexi&ie=utf-8&oe=utf-8&client=firefox-b
Melde-Rayleigh-Experiment et cet.
--------------
                                 C. O. P.  actually in average of industrial split-heat pumps :

                 U.S. gov studies end70'/80'/90'/.... and DE FRAUNHOFER INSTITUTES 201...
                                           < = 1 , not P but PE is the source calculation divisor :

                                average heat pump work C.O.P. :  < 2,0.  / (  average PE/ electric P  ) C.O.P. :  - 2,0         
                                   Primary Energy (PE~" Power") / Electric Energy ( "Electric Power")

                                                                  < 2,0 / - 2 =

                                                                  < 1 as Total on-grid C. O. P. 


                                in households cable-grid-losts .........( ? Meters cable   P- source   to   P-consumer ?)
                                               positive C. O. P. ~ gain, win and negative C. O. P. ~ losts

                                    1 important PARAMETER : CIRCUIT LENGTH ( / VELOCITY)           

                                      and the number of conversion steps ( load flow barrier)       


                   https://translate.google.com/translate?hl=de&sl=de&tl=en&u=https%3A%2F%2Fde.m.wikipedia.org%2Fwiki%2FKirchhoffsche_Regeln     
                   BUT:     when not  :   .......=  0
                   then                 
             
                   https://translate.google.com/translate?hl=de&sl=de&tl=en&u=https%3A%2F%2Fde.m.wikipedia.org%2Fwiki%2FAmp%25C3%25A8resches_Gesetz
                   AMPERES LAW + MAXWELL'S " DISPLACEMENT CURRENT"- extension               


                  to become an  " UNIVERSAL AMPERE- MAXWELL LAW"

                  but because AMPERE LAW = LAPLACE LAW = BIOT-SAVART LAW

                  "LAPLACE-MAXWELL LAW" AND " BIOT-SAVART-MAXWELL LAW" are equal


                   ERGO : " AMPERE-LAPLACE-BIOT-SAVART-MAXWELL UNIVERSAL LAW"
                                 
                   https://de.m.wikipedia.org/wiki/Amp%C3%A8resches_Gesetz

                           thermodynamic Carnot circuit :
                  evaporator,  condensator,  Drossel,  compressor  + fluidum ( f.e.  Butanol- liquid  - 78°C)

                          electrodynamic Carnot charge acceleration/deceleration  circuit  :

                                                                              Drift-Strom             

                                                  Raumladungsdichte x Driftgeschwindigkeit
https://translate.google.com/translate?hl=de&sl=de&tl=en&u=https%3A%2F%2Fde.m.wikipedia.org%2Fwiki%2FElektrische_Stromdichte

[v8karlo]

   Looks like the feed back circuit is returning less than 100mA to the 12v battery. Which would not keep the battery up for very long, if a 25w bulb or bigger bulb were used as the load.
   But, there is no actual output readings, at the bulb, to compare with the input current.
   Karlo: here is a link to the "double diode loop" by Dr. Stiffler.
   https://youtu.be/8VRqf8E8VIM
   I also have some videos about that circuit, or at least my versions of the Docs device, if interested.
   You can look on youtube,  just search for my name, Nick Zec.
   Or for my youtube channel.   Here is my last video about the diode loop.: https://youtu.be/BZsvtlA_Rgc

It draws from battery 90mA an returning 110mA.


But it also means that primary coils eats 200mA and returning 110mA. That coil is only 50% efficient.


Great way to see efficiency of transformer.