Getting energy from asymmetry of the magnetic field experiment

[telecom]

almost 3 to 1!
How do you cycle it?
Let it move from left to right?

[ayeaye]

Let it move from left to right?

Yes, but there is friction. I calculated friction too, above.

[sm0ky2]

What I mean is, Force is only Force.
Force over distance is work.
This time it takes for that amount of work to be done
derives the energy.


Force/distance/http://www.theochem.ru.nl/~pwormer/Knowino/knowino.org/wiki/Joule_(unit).html
Having only force, you have no energy.
Having force over a distance (and I promise you, wether or not
your scales show you, the force is not constant over that distance)
gives you work.
But you don't know how much energy it took to do that work unless
you know how much time the force was applied over that distance.


Thus, I still remain confused about how you are seeing "energy".


Also, as I tried to relay in my previous posts, one side of the field affects
the other. Your "neutral point" is an effect of both the S and N poles.
Change the size or location of your metal nut and watch how the angle/distance changes
for your experiment.


I can make the 'fabled' monopolar magnet. And they do not work like we expect.
They are the same as any other magnet, just having only one pole.
The mono field takes on the same shape and attributes as the dipole.
Push on one and it distorts the other.
The total field remains the same always.

[sm0ky2]

The actual unit of a Newton is a time based quantity.
Those spring scales are calibrated on 1 Kg*m /s/s
You are measuring a static force like weight. Not an
acceleration force like gravity. Which is what the Newton is.


The force has to be applied for a distance over a time.
This is energy.
In this tutorial (mostly showing how to 0 your scale):
the user is allowing gravitational acceleration to provide
the time derivative force.


Magnetic fields exist outside of the time domain.
Time is only considered when an object is moving through
the field. A static force causes the scale to work like a weight
scale. Showing you kg/m. Not Kg/m/s/s.

Also, don't calibrate it vertically unless you are measuring vertical

[ayeaye]

What I mean is, Force is only Force.
Force over distance is work.

I said that i measured both forces and distances, and from that calculated energy. See how i did my calculations above.