Getting energy from asymmetry of the magnetic field experiment

[telecom]

the forces in kg x distance in cm are like that
from the left:
0 - .16
1 - 0.06
2 - 0.08
3 - 0.08
4 - 0
5 - 0

from the right:
0 - 0.08
1 - 0.10
2 - 0.12
3 - 0
4 - 0
5 - 0

[telecom]

Next week will try doing more measurements.
Can someone analyze the data?

[telecom]

At the end of the  ravel to the right there is a very strong perpendicular force pushing the magnet away from the setup

[ayeaye]

the forces in kg x distance in cm are like that
from the left:
0 - .16
1 - 0.06
2 - 0.08
3 - 0.08
4 - 0
5 - 0

from the right:
0 - 0.08
1 - 0.10
2 - 0.12
3 - 0
4 - 0
5 - 0

Looks nice.

By fast calculation it is 0.38 kg * cm at left and 0.3 kg * cm at right (just add all numbers at left and at right side), better to convert it to Newton * mm or milli Joules.

This confirms my results.

More energy at the left side than at the right side. Also there is a significant force a longer distance at the left side than at the right side. Though the difference of energy is less.

[ayeaye]

I notice that your small moving magnet is rather wide, i used a much narrower small magnet. I'm not sure whether it's true, but how i see it by now, any irregularity of the field there may be, a wide moving magnet may make it all more even, something. If you have only one kind of magnets, these with poles on the wider sides, if you have them too many, and if they are ceramic magnets, maybe split some to half in the middle, sorry to recommend that... What i can say by now.

Should not be difficult to replicate the way Telecom did it. Like if you have an aluminum or a plastic ruler, make it stand 90 degrees on the side, should not be too difficult for these who have done things with their hands.