Free energy from gravitation using Newtonian Physic

[pequaide]

I think that those that constructed the Atwood simulation assumed that the mass distribution of the pulley was like that of spokes. The spoke arrangement would allow equal mass at every distance from the point of rotation. This uniformity of mass allows momentum (of the concentric hollow cylinders) to be a linear function as the radius is increased from the point of rotation to the circumference. And the average momentum is at half the distance from the center to the circumference. If the mass distribution of the pulley is like that of a solid disk this (average momentum location) is not true, because mass and velocity would increase as the spinning concentric rings (being evaluated) approach the circumference (subdivide the disk into a hundred concentric rings). The average momentum of the solid disk is at about 58% of the distance from the center to the circumference.

[pequaide]

www.msu.edu/user/brechtjo/physics/atwood/atwood.html   I was hoping that typing in the site would post a link to the site. 

Put 1000 (average momentum is half way to the circumference, effectively 500 kg) kg in for the mass of the pulley, and 2 kg and 3 kg for the masses of mass 1 and 2. Then calculate the momentum of the pulley after a 1 meter drop. d = 1/2v?/a: a = 1/505 * 9.81

And then calculate the momentum of one kilogram that has dropped one meter. The difference between mass one and mass two is only one kilogram.

And then remember that there is a Law of Conservation of Momentum.

Transfer the momentum of the pulley to the one kilogram and you have a huge amount of energy.

[Kator01]

Hello pequaide,

thank your very much for your effort in continoiusly explaining more and more of some important details.
Looks I am the only one left at the time as a discussion-partner.

I plan to build a simple version with a disc and spheres. The spheres in my model are attached to a ball-bearing fastened to a center-axis.
This is different mechanically in comparison to your experimental setups in the sense that
the center-point of the tethers can rotate freely and do not wind up on the axis.

My question is this : What would you expect to happen according to your experience ?
I will read this attwood-page and come back to this thread if I have new ideas/insights/ etc.

Regards

Kator

[pequaide]

A disc is fine; I use one for the air table model. But you must wrap the tether of the spheres around the circumference of the disc at least one disc radius. I have no model much shorter than one cylinder radius, but they might work depending on the difference in the spheres' mass to cylinder mass.

As the tether unwraps from the disc the force in the tether forces the disc to accelerate (decelerate; reduce the rate of spin) in the opposite direction, the disc will slow down and stop and then begin rotating in the opposite direction.  If you release the tethered spheres when the disc is stopped the disc will of course remain stopped, and the spheres would be at maximum velocity.

I am going to insert a picture of an air table model, since a photograph is worth a thousand words.

The screwdriver goes through a hole that captures a loop on the end of each string. In operation there is a pin in this hole that is tied to a string that is looped around the operator?s finger.

The pucks on the end of the strings must unwrap from the disc about one radius. The loose strings are held up against the plastic wall, by the fingers, and they hold the pucks in place as the disc is accelerated.  When the disc is released the strings are released and the pucks will unwrap from the disc. If you pull the pin when the disc is stopped the disc will not be restarted, in the opposite direction. The system works very well.

[pequaide]

Let me review something in this model. If the pucks stop the disc before the string is at 90? (to a line tangent to the circle at the point where the string enters the circle) then the disc will be restarted in the opposite direction (unless of course the string is released).

By adding mass to the disc the disc can be stopped just as the string becomes straight. In this model the string leaves the disc at 90?.  The 30 pound test line was used for photographic reasons. 10 lb test would work for the air table.

Kator01 Possibly a better answer to your question about whether your design will work or not would be this; how are you going to stop the momentum of the spinning disc? How are you going to apply force to the disc in the opposite direction of the spin?