Simple to make Hilden-Brand style motor

[gyulasun]

It is not a good OU thread without a bit of mystery

Well,  basically you are right but the problem is many members here either speak nonsense in a believe they have something good (but they don't) or simply tease people to have fun...  This is supposed to be an open forum for sharing and if someone has got a brilliant idea, he or she should either follow through it into a marketable (small or big, whatever) product or if he is not capable to do so then he should look for some help, advice etc (not money) to achive his goal.

rgds,  Gyula

[i_ron]

Well,  basically you are right but the problem is many members here either speak nonsense in a believe they have something good (but they don't) or simply tease people to have fun...  This is supposed to be an open forum for sharing and if someone has got a brilliant idea, he or she should either follow through it into a marketable (small or big, whatever) product or if he is not capable to do so then he should look for some help, advice etc (not money) to achive his goal.

rgds,  Gyula

Gyula,

LOL, It was not a brilliant idea necessarily... just a sim.  It was primarily for me so the password you could try would be "iron" (less the quotes)

I had hoped to get to it yesterday but the forces in the gap are of an extreme nature causing the insert to favor one side or the other. My build was not strong enough to keep the insert centered and so my experiment was not conclusive, but I think what it was showing is that there is no further movement of the insert into the gap once the last part of the insert has entered into the gap. Not unlike the operation of a solenoid, no matter how short the plunger is in comparison to the length of bore, the plunger will tend to center... then cease further pull in.

As common sense dictates the "pull in force" is greatest with the insert part way out of the gap and reduces to zero when fully entered, as my charts for a different mode of operation show (with the bar passing at 90 degrees on the outside of the pole pieces)

However, good question to lanca! 

Welcome to the group lanca, hope to hear more on this subject.

rgds, Ron

[yssuraxu_697]

Well,  basically you are right but the problem is many members here either speak nonsense in a believe they have something good (but they don't)

Exactly, so I do not want to post around pics from low quality sim with people around who may blindly copy or reproduce them and make OU research even more of a trashbin. The problem was that at the given moment I had no other way to send it to i_ron (PMs dont allow attachments).

[gyulasun]

  

Hi yssuraxu_697,

I had no idea the zip file was meant for Ron... otherwise I would not have made any notice.   

Gyula

[Nali2001]

PP Problems:

In static mode the parallel path model has a magnet strength gain of nearly four.

Yet several factors work to negate this in actual practice.

Primarily, the worst offender is that the flux will only switch, with the four times advantage, when the bar is fully aligned with the main bars.

I have prepared a simple chart from actual numbers to illustrate this fact... chart one. The gauss numbers are actually unreferenced milli volt numbers but are used to indicate the trend.

That is, the smallest distance is 1/8th of an inch that the bar has covered the main bars and the gauss is very weak at "45". The bars are in each case 1 inch CR steel so when the two bars are fully aligned, meshed, TDC, what ever term you wish to apply... then the Gauss has reached its maximum at the distance covered of ! inch.

In chart 2 we see the Kg's versus distance covered. In this case, on approach the Kg's are zero but the maximum pulling force to align the bar occurs just as the bar has covered the main bars by 1/8th of an inch. When the bar reaches full alignment the pulling force is zero. I am speaking of a rotary machine here, not the reciprocating model previously mentioned. So all same as any motor, when the poles are fully aligned, then there is no further rotational force left to operate said machine, understood?

But here we see the Achilles heal of Parallel Path machines. The maximum pulling force occurs just as the poles start to align but this is the period of minimum flux strength! And when the flux strength reaches maximum, at full alignment, then the 90 degree vector driving the machine in rotation has reached zero.

Maximum flux strength (our four times gain) = zero rotational drive.

Ron

Very good work Ron.
Nice detailed report and tests. Lol to see you probably print and scan these graphs.
Yes it's a shame that the magnet won't really switch that well when resistances like air gaps are involved. Well you 'could' switch them over big air gaps, only thing is that you will be needing much more input. Which more or less goes against the whole 'energy efficient' principle. I wouldn't surprise me if Flynn uses microscopic air gaps. Plus I think he only switches 'on' when the alignment is at least 25%+ established. So no open space switching when there is not yet much alignment. Drawback of this is that the attraction moment is very short, but than again the Flynn motor has many poles, so the attraction is more or less continuous. Plus it could be that he uses an initial input which is of much higher current to hard switch the magnets despite the less than optimal alignment, and then drop off current when alignment gets better. And then again, he is not stating over 90% efficiency on his site, but there could be other reasons for that.