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Overunity Machines Forum



Chas Campbell free power motor

Started by TheOne, June 04, 2007, 10:25:17 PM

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0 Members and 36 Guests are viewing this topic.

hansvonlieven

G'day Stefan,

How will you get the extra ball there??

Hans von Lieven
When all is said and done, more is said than done.     Groucho Marx

zero

Hans, you still have not accounted for z travel forces.

shruggedatlas

Quote from: zero on September 07, 2007, 08:44:13 PM
Humbugger, I never swore at anyone.  But to deny a fact is just that.  A denial
of the true potential.
---

Also, curious if we remove some ball load chambers what will happen:


I do want to chime in on this bit.  In Chas's device, it is impossible for the balls to impart their momentum to the wheel, because each ball bumps into the balls in front of it, which in turn bump into the catch.  You cannot remove the catch from the equation, because a ball cannot enter the ramp at any time - there has to be a receptacle for it.  You also cannot reduce the number of balls, because it takes time for the ball to roll down the ramp and get into position.

Humbugger

Quote from: hartiberlin on September 07, 2007, 08:56:17 PM
Quote from: Humbugger on September 07, 2007, 08:47:34 PM
Stefan

Your error is simple.  There is never a time when two balls are on the right side if the radius is 4.  Some of the time, there is no ball on the right side in any configuration based on 30 degrees and over 3.8763 radius.

I have been saying this all along but you have not heard or understood.

Hum


Hum,
you could build a wheel always so that there is at least one ball at the right side...
Also you could slow the wheel down or stop it, so
one ball will always be at 4x distance at the right side...

Wrong!  Please just go and look at the diagram i drew.  If the radius is greater than 3.8763, there will be times when no ball is on the right.  There will never be two balls on the right.

Hum

http://www.overunity.com/index.php/topic,2487.msg48099.html#msg48099

hartiberlin

Quote from: hansvonlieven on September 07, 2007, 08:53:12 PM
G'day again,

Picture 1 shows exactly what I am talking about. The ball on the right moves in a 26.2 degree arc, therefore on any other concentric circle the movement is 26.2 degrees, insufficient to load the next ball, which requires 30 degrees. It does not matter how much force you have, the movement stops at 26.2 degrees because that is when the ball that does the work leaves the system. At this point the system reverses.

Hans von Lieven

But you have a 3.9 to 3.6 advantage from the torque arms that is stored as energy in
the big (fly)wheel, so the missing 30 - 26.2= 3.8 degrees are easily pulled up....
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