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Overunity Machines Forum



Chas Campbell free power motor

Started by TheOne, June 04, 2007, 10:25:17 PM

Previous topic - Next topic

0 Members and 35 Guests are viewing this topic.

tinu

Quote from: hartiberlin on September 09, 2007, 06:11:21 PM
Tinu,
you did not analyze my last picture.
Things change, when you different setups.
I now have always only 1 ball at the right side, not 2.

I will try to calculate it tomorrow with your formulars
and then we will see, where the error is.

It doesn?t really matter.
The result will always be zero.

I?ve told it before: it?s difficult to write a demonstration that is valid for any conceivable case. But for any n, R, the simple math shows zero torque.

Tinu

P.S. Simple copy-paste; srry for it:

Ok, here it is for your second case, Stefan:

Angle a=30 degrees
if  m- mass of each ball, assume m*g=1, for simplicity
Right: 1 ball
Left: 5 balls (as per your second picture)

Torque:
Right: Rext*cos(a/2) ; I guess here was your error. The ball is at 15 degrees
Left: Rint+2*Rint*cos(a) +2*Rint*cos(2*a)

If Rint=1, Rext=Rmax theoretically possible for 12 total slots and 1 on the right = 3.8637, you?ll have:

Right: 3.8637* 0.96592 = 3.7321
Left: 1+2*0.866 + 2*0.5 = 3.7321

Great! The wheel stays!

See? It?s exactly the same!

Humbugger

Quote from: hansvonlieven on September 09, 2007, 06:22:14 PM
except Hum at 3.8673x the inner you do not have enough torque to lift the other balls

Hans von Lieven

I always have enough torque to lift my balls...even without Viagara...

I want to know, since i have once again been accused of ridiculing and being a naughty bad skeptic, just how you stick an integer number of cups evenly around a circle at 29 degrees apart.  Until I get that answer from Stefan and his confession that the "change it to 29 degrees" idea was absolutely absurd, i'm going to shut up and have a shot of single malt.

Hum

gaby de wilde

Quote from: Humbugger on September 09, 2007, 08:57:36 AM
Gaby demonstates that he was not following the earlier discussion where Stefan suggested that Charles's wheel could not work unless the ratio of outer radius to inner radius were larger than Charles 2:1 ratio.  Stefan did simple torque arm math that convincingly showed this for the 2:1 case. 

http://www.overunity.com/index.php/topic,2487.msg48064.html#msg48064

Others joined in, I among them, and an excellent discussion raged for an hour or more.  I don't recall Gaby participating. 

One of the ideas proposed was that there was no limit on the ratio. 

Another was that there would always be at least one ball on the right side of the wheel no matter the size.  Another was that there are times when two balls ride the right side when the ratio is 4:1.

All three of those assertions are untrue and I set out to show that.  All of it simply leads to the conclusion, if the simple math is done correctly, that the torque moments are always equal and opposite for a full cycle.

Quote from: tinu on September 09, 2007, 09:17:10 AM
P.S. Don?t bother gaby; he?s above us all; well above and out of this world?


*edit*
The balls spiral inwards cuz that makes it spin faster (in case that wasn't obvious)
blog  | papers | tech | inventors  | video

rMuD

Quote from: zero on September 09, 2007, 05:47:32 PM
Thats not true Hans,

The energy of the Impact when that ball hits hit back will be
much greater than it just set or resting there.


1) Take a teeter,  and put one ball on one side.
2) set a ball on the other side.

result = teeter ballances

1) take teeter and put one ball on one side.
2) drop a ball from 3ft at the other side

result = other sides ball will fly off the teeter.


think about what you said here...  if your knocking a ball up...  if it was more energy.. wouldn't the other ball go up further than where you dropped the other ball from?  which then falls and the other ball goes up even higher?    circus preformers bodies in orbit?

go out in the back yard, put two baskets on the ends of a 2x4 and chair in the middle where it's balanced.. or a axle :)    do drop tests.. you will find that as long as you do not drop the ball further than the distance the teeter totter can move your not going to have a flying ball..  and if you go beyond that..  you aren't going to exceed the height you started with, from mechanical loss, also a signifigant lost from the fact that when you impact the teeter totter with the falling ball, some of the energy has to be absorbed by the board because it cannot accelarate instantly


I'll draw a picture :)

hansvonlieven

Zero. you seem to think that if you run a ball down a PVC pipe you can gain energy, quite the contrary, you lose some.

I suggest the study of an elementary text on physics. Inclined planes would be a good place to start.

Oops sorry, I forgot science is wrong on everything.

Sorry.

Hans von Lieven
When all is said and done, more is said than done.     Groucho Marx