gravity wheel question

[alibaba]

simple question

in the attached image:

a rotating wheel. 12 arms ( 1 meter each ) . a ball (1kg) attached with a smaller arm . The green arrow shows the desired direction of rotation. in grey position the ball is resting on the long arm.in red position the ball is hanging by the small arm due to gravity.

my question is : what will be the result when the mass of upper most ball shifts from grey to red postion. will it influence the rotation direction of the wheel ? i have no illusion that the shifting of the mass from grey to red and back when when it reaches the appropriate position will in anyway mak the wheel turn. what i need to figure out ia a method which will allow the mass f the balls to shift from their grey-red-grey postions without disrupting the rotation of the wheel.

i hope i have clearly outlined my question.

thanks to every one.

[TheOne]

the problem with gravity wheel is they will always "balance" and never work, it take the same force for the mass to go up and go down, to get an unbalance effect you need to use external device such as hydrolic/compressed air to move some of the mass to shift a mass

[pequaide]

Add an extra sphere to the descending side; keep all of them against the post. This will cause an acceleration 1/13 that of a lone sphere. After the extra sphere descends one meter the wheel will have a velocity of 1.228 m/sec and 15.97 units of momentum. If you transfer all the momentum back to the extra sphere and release it, it will raise 13 meters. The momentum transfer can (according to my data) be achieved by the cylinder and spheres experiment.

The distance formula is used to determine the distance an object will rise if it has a certain velocity.   d = 1/2at?   t? = v?/a? therefore d = ? v?/a 

So: if an object has a velocity of 1 m/sec it will rise .051 meters.

If an object has a velocity of 4 m/sec it will rise .8155 meters.

.8155 /.051 = 16

So if the Law of Conservation of Momentum is true for the cylinder and spheres experiment (where, in one model, four units of mass give all their motion to one units of mass) it quadruples its energy content in a few tenths of a second. 

Also; if one unit of mass accelerates 4 units of mass (as in an Atwood?s machine) while falling .2039 meters, it will have a velocity of 1 m/sec. 1/2v?/a or √(2 * 9.81/4 * .2039) = 1 m/sec.  In this why only one object is being raised and lowered, but you get the same increase to 400% of the original energy. Because: if the now moving Atwood gives all the motion back to the mass that was dropped it will raise .8155 meters.

The time over which the force (of the ? extra mass) acts in the Atwood to drop .2039 m is the same as the freefall time for a dropped distance of .8155 m.  Reverse freefall (the trip back upward) also requires the same amount of time.

If a quantity of motion is caused by a certain force applied for a certain period of time, one would expect that an equal amount of force would have to be applied in the opposite direction for an equal amount of time in order that the motion is stopped. This process does not violate Newtonian Physics; F = ma, The Law of Conservation of Momentum, Newton?s Three Laws of Motion, etc... It does however; make energy.

A cycling machine would be very impressive, but none will deny that a one kilogram object moving 4 m/sec has four times as much energy as four kilograms moving 1 m/sec. Experimenters only need to verify that Newtonian Physics holds in the cylinder and spheres experiments. 

[Mr.Entropy]

I see no one answered your question, so:

my question is : what will be the result when the mass of upper most ball shifts from grey to red postion. will it influence the rotation direction of the wheel ?

The forward torque on the shaft that a fixed ball would produce after it crosses the 12 o'clock position is delayed as the ball falls to its new position.  In fact, there is even a tiny reverse torque as its weight pushes against the short arm.  Then, as the short arm collides with its restraint, a greater forward torque is applied momentarily as the ball is decelerated.

The torque is modulated a bit at the bottom, too.

Ignoring impact losses, all the torque variations even out in the end, so that the average power (torque * rpm) applied to the shaft by one or any number of weights is zero, regardless of the direction or speed of rotation, so the wheel will not have a preferred direction overall, although for short moments it will prefer one direction, and then the other.

In real life, you will lose some energy to heat and sound as the ball hits its red or grey position restraints, and these losses aren't necessarily the same in both directions, so the wheel may indeed turn more easily in one direction than the other.

i have no illusion that the shifting of the mass from grey to red and back when when it reaches the appropriate position will in anyway make the wheel turn. what i need to figure out ia a method which will allow the mass f the balls to shift from their grey-red-grey postions without disrupting the rotation of the wheel.

Well, the weights flapping around would tend to make the rotation a bit bumpy.  The easiest way to smooth it out is to attach a big heavy flywheel to the shaft, so that the variations in torque produce only small variations in speed.

Cheers,

Mr. Entropy

[hansvonlieven]

G'day all,

This kind of idea has been around since Bessler's time. Bessler in his "Maschinen Traktate" sketches a very similar device.

It does not work.

Hans von Lieven