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Overunity Machines Forum



The Lee-Tseung Lead Out Theory

Started by ltseung888, July 20, 2007, 02:43:44 AM

Previous topic - Next topic

0 Members and 62 Guests are viewing this topic.

hansvonlieven

G'day Top Gun and all,

DEFINITION - The newton is the Standard International (SI) unit of force. In physics and engineering documentation, the term newton(s) is, usually abbreviated N.

One newton is the force required to cause a mass of one kilogram to accelerate at a rate of one meter per second squared in the absence of other force-producing effects. In general, force (F) in newtons, mass (m) in kilograms, and acceleration (a) in meters per second squared are related by a formula well known in physics:

F = ma

The formula also applies when F and a are vector quantities having magnitude and direction:

F = ma

where the direction of the force vector F is the same as the direction of the acceleration vector a.

You say:    (2)    The Old tension before the horizontal force = T = Mg = 1 x 9.790 Newtons.

This is nonsense. The tension on the string at rest is precisely 1 kg. You are using the gravitational accelleration as your value, which is not legitimate, by definition.

Hans von Lieven
When all is said and done, more is said than done.     Groucho Marx

Top Gun

Quote from: hansvonlieven on December 07, 2008, 02:02:27 PM
G'day Top Gun and all,

DEFINITION - The newton is the Standard International (SI) unit of force. In physics and engineering documentation, the term newton(s) is, usually abbreviated N.

One newton is the force required to cause a mass of one kilogram to accelerate at a rate of one meter per second squared in the absence of other force-producing effects. In general, force (F) in newtons, mass (m) in kilograms, and acceleration (a) in meters per second squared are related by a formula well known in physics:

F = ma

The formula also applies when F and a are vector quantities having magnitude and direction:

F = ma

where the direction of the force vector F is the same as the direction of the acceleration vector a.

You say:    (2)    The Old tension before the horizontal force = T = Mg = 1 x 9.790 Newtons.

This is nonsense. The tension on the string at rest is precisely 1 kg. You are using the gravitational accelleration as your value, which is not legitimate, by definition.

Hans von Lieven

Dear Hans,

Tension is a force.  As you pointed out, the unit of force is in Newtons.
Mass is measured in Kilograms. 

As pointed out by Tinu at the beginning of this thread (reply #4 and following), many non-physicists confused the two.  The most common mistake for the layman is to say - I weight 50 kilograms.  In reality, the correct physics statement is - I have a mass of 50 Kilograms.  The force I exert on the scale is Mg or 50 Kilograms x 9.70 meters per sec per sec in Hong Kong.

Tinu used the above to say that I was no physicist.  I correct that subsequently.  You should understand the above too.

Top Gun

Quote from: TinselKoala on December 07, 2008, 01:34:27 PM
Before we get too far into the "change of subject" most conveniently tossed in, let's get back for a moment to JLN's replication of Bull's work, which is nearly exactly  LTseung's experiment001.

This experiment failed to support the LTLOT.
JLN's analysis is correct.

What is wrong with JLN's experiment, what is wrong with his analysis, and why doesn't it apply to your "flying saucer"?


Please wait.  We shall have experimental results for the exact Experiment001 shortly.  There will be much juicy discussions then.

hansvonlieven

Quote from: Top Gun on December 07, 2008, 04:12:39 PM
Dear Hans,

Tension is a force.  As you pointed out, the unit of force is in Newtons.
Mass is measured in Kilograms. 

As pointed out by Tinu at the beginning of this thread (reply #4 and following), many non-physicists confused the two.  The most common mistake for the layman is to say - I weight 50 kilograms.  In reality, the correct physics statement is - I have a mass of 50 Kilograms.  The force I exert on the scale is Mg or 50 Kilograms x 9.70 meters per sec per sec in Hong Kong.

Tinu used the above to say that I was no physicist.  I correct that subsequently.  You should understand the above too.

The gravitational constant, denoted G, is an empirical physical constant involved in the calculation of the gravitational attraction between objects with mass. It appears in Newton's law of universal gravitation and in Einstein's theory of general relativity. It is also known as the universal gravitational constant, Newton's constant, and colloquially Big G.[1] It should not be confused with "little g" (g), which is the local gravitational field (equivalent to the local acceleration due to gravity), especially that at the Earth's surface; see Earth's gravity and standard gravity.

1 kg-force is equivalent to 9.80665 newtons not the stated 9.790

Hans von Lieven
When all is said and done, more is said than done.     Groucho Marx

TinselKoala

Quote from: Top Gun on December 07, 2008, 04:17:51 PM
Please wait.  We shall have experimental results for the exact Experiment001 shortly.  There will be much juicy discussions then.

A shameless dodge.

You, who claim to be a "scientist", should know that science proceeds by attempts at falsification of theories, not by confirmatory experiments. I have no doubt that your "exact" experiment001 will perform as you say--because you will not be testing it in the recommended manner. You will not be showing it to hover. You will not be showing it to make progress while on a proper frictionless substrate. You will not be showing it maintaining a constant displacement on a pendulum test. Why will you not be showing these things? First, because the device will not do them. Second, and more importantly, you will not do any appropriate control experiments, because at some level, you know what will happen.
And so do I.
What you will show is the device making some progress while on a table top. Just like the earlier video. And this will prove absolutely nothing about your theory, other than that you do not understand the logic of scientific hypothesis testing. Which we already know.

Now, address the issue. JLNaudin's device is functionally identical to your experiment001 device. Why did he come to the conclusions he did?