The Lee-Tseung Lead Out Theory

[broli]

Yes if you are measuring across a resistor then I see no problem. But the full wave bridge rectifier (FWBR) suggestion still applies. I don't know about the input/output voltages are but if the COP is high and since your input is DC one should be able to simply us a transformer with a FWBR and filter behind it. These parts are quite cheap.

[chrisC]

....

Hope that clears the doubts from some Forum Members.

It is no wonder you're making a fool of yourself on this forum. You need to understand reactive circuits and real world power measurements.

ps: If OU is so easily achieved by some deluded 'scientist' then the rest of the real world must be living on some unreal planet!

cheers
chrisC

[Paul-R]

It is no wonder you're making a fool of yourself on this forum. You need to understand reactive circuits and real world power measurements.

ps: If OU is so easily achieved by some deluded 'scientist' then the rest of the real world must be living on some unreal planet!

cheers
chrisC

You have been told where to go for explanations, chrisC. You are either a wanker or someone
who is paid to attempt to sow dischord.

There is, of course, a third alternative; namely that you are both.

[Paul-R]

Yes if you are measuring across a resistor then I see no problem. But the full wave bridge rectifier (FWBR) suggestion still applies. I don't know about the input/output voltages are but if the COP is high and since your input is DC one should be able to simply us a transformer with a FWBR and filter behind it. These parts are quite cheap.

If the output is 30 volt AC, it would be a simple matter to apply a mains transformer from a
microwave oven, being 8:1, and end up with 240v AC.

[utilitarian]

From: http://hyperphysics.phy-astr.gsu.edu/hbase/electric/powerac.html

AC Power

As in the case with DC power, the instantaneous electric power in an AC circuit is given by P = VI, but these quantities are continuously varying. Almost always the desired power in an AC circuit is the average power, which is given by
Pavg = VI cosφ

where φ is the phase angle between the current and the voltage and where V and I are understood to be the effective or rms values of the voltage and current. The term cos φ is called the "power factor" for the circuit.

For pure resistive circuits, the power factor is 1.

Thus we can use the same equation for both DC and AC if we have pure resistive load.

Hope that clears the doubts from some Forum Members.

There will always be doubts until you can make a device that powers itself.  Isn't it pretty foolish to brag about a machine that makes energy, and at the same time have to plug it into a wall outlet?