The Lee-Tseung Lead Out Theory

[ltseung888]

The Ms. Forever Yuen Magnetic Pendulum Experiment

Ms. Forever Yuen gave me her powerpoint presentation with photos on her Magnetic Pendulum Experiment last night.

I have edited and attached it here.

It is easier to set up than the toy from the overunity.com store.  It is much cheaper too.  The important element to look for are the three sets of readings:

(1) No other magnetic material around (32 Oscillations per 30 sec)

(2) Repulsion (25 Oscillations per 30 sec)

(3) Attraction (41 Oscillations per 30 sec)

I shall continue to discuss the significance of this experiment in the coming posts.

Thanks to Ms. Forever Yuen once again.

Lawrence Tseung

[Mr.Entropy]

Now consider exactly how we supply energy to the stationary pendulum.  The pendulum is hanging in the vertical position.  We apply a horizontal Force F.  The pendulum will have both a vertical and a horizontal displacement. (The D vector mentioned by Mr. Entrophy).  Just before we stop the force F, there will be THREE forces involved in the pendulum system.

(1) The Weight of the Pendulum (or more exactly m *g where m is the mass and g is the gravitational acceleration at the surface of the Earth which is 9.8 m/s/s approxiately.  Please yell if you don't understand the statement)

(2) The Horizontal Pulse Force F (Note that it is an externally applied Force controlled by the Engineer. )

(3) The Tension  of the String (If there were no string, the pendulum will not swing back)


Bill rightly stated that these three forces are also vectors.  In order to determine the energy supplied by these three forces, we need to apply the vector mathematics of Force * Displacement.  (Note that it is Vector Mathematics and not the scalar multiplication.)

The relationship of the forces MUST obey the Law of Parallelogram of Forces.  That set of Laws is taught at Mechanics 101 in secondary school physics.

I shall pause here to get your response first.

Right let the displacement D represent the path of the pendulum bob durring the application of the pulse force. Assuming that the displacement D is small enough, since a pulse lasts only a moment, we can consider D to be a straight line and the forces below to be constant over the time when the pulse is applied.  Otherwise we'll have to integrate:

During the pulse time, we have a force due to gravity (Fg), a force due to the tension on the string (Fs) and the applied pulse force (Fp).  By the law of the parallelogram of forces, as you say, these add vectorially, so that the work done by the combination of those forces is W = (Fg + Fs + Fp) \dot D

The \dot product is distributive over addition, so W = (Fg \dot D) + (Fs \dot D) + (Fp \dot D), and we can consider each of these independently:

(Fg \dot D) is the work done by gravity.  If the bob is moving up, Fg and D are in opposing directions and this is negative.  work is done against gravity and stored as potential energy by the increase in the bob's height.

(Fp \dot D) is the work done by the pulse force.  You will probably apply the force in the direction that the bob moves, speeding it up, so this will be positive.  This work will be stored as an increase in the speed and kinetic energy of the pendulum.

(Fs \dot D) is the work done by the tension on the string.  Since the force is applied at a right angle to the direction of motion, Fs \dot D is zero, and the string does no work.

That's the conventional analysis.  What in here is incorrect?

Cheers,

Mr. Entropy

[ltseung888]

Lawrence:

So, then might it be possible to contruct a decent size pedulum where the "weight" would be a cylinder shaped magnet and suspend it from two lines into one such that it would keep it from twisting, and have it pass twice during it's period through a coil, or a series of coils, to generate enough power to run a small occilator that would add enough of a pulse at the correct time to maintain the pendulum motion?  This would be fairly easy to construct on a smaller scale for testing.  Do you think this would be possible?  thanks.

Bill

Dear Bill,

I believe you should read the Bill Mehess Motor first.

http://www.overunity.com/index.php/topic,919.msg6407.html#msg6407

I advise a more thorough understanding of the Lee-Tseung theory first before more experiments.  There are already 300 or so Over Unity Inventions worldwide.  Most of them are from "experimenters" who jumped to try some ideas without the painstaking research first.

Many almost got it but then spent years spinning around.  We can discuss how to improve some of them here and then do the improvements. 

I shall wait for a few more comments or responses on the Ms. Forever Yuen experiment before further continued discussion of the Lee-Tseung Theory.

Regards,

Lawrence

[ltseung888]

Right let the displacement D represent the path of the pendulum bob during the application of the pulse force. Assuming that the displacement D is small enough, since a pulse lasts only a moment [1], we can consider D to be a straight line and the forces below to be constant over the time [2] when the pulse is applied.  Otherwise we'll have to integrate:

During the pulse time, we have a force due to gravity (Fg), a force due to the tension on the string (Fs) and the applied pulse force (Fp).  By the law of the parallelogram of forces, as you say, these add vectorially, so that the work done by the combination of those forces is W = (Fg + Fs + Fp) \dot D

The \dot product is distributive over addition, so W = (Fg \dot D) + (Fs \dot D) + (Fp \dot D), and we can consider each of these independently[3]:

(Fg \dot D) is the work done by gravity.  If the bob is moving up, Fg and D are in opposing directions and this is negative.  work is done against gravity and stored as potential energy by the increase in the bob's height.

(Fp \dot D) is the work done by the pulse force.  You will probably apply the force in the direction that the bob moves, speeding it up, so this will be positive.  This work will be stored as an increase in the speed and kinetic energy [4] of the pendulum.

(Fs \dot D) is the work done by the tension on the string.  Since the force is applied at a right angle to the direction of motion, Fs \dot D is zero[5], and the string does no work.

That's the conventional analysis[6].  What in here is incorrect?

Cheers,

Mr. Entropy

Let us discuss your assumptions point by point.
[1]We assume that the Pulse Force is controllable by the Engineer.  It can be as short or as long as desired.  In this case of the first application on the stationary pendulum, we assume that the Pulse Force is long enough to let the pendulum swing fully to its new position.  At the new position, the pendulum stopped momentarily to change direction to swing back.

[2] The forces are constant over time. 

The Gravitational Force (Fg) can be regarded as constant as the mass and the gravitational acceleration (g = 9.8 m/s/s) can be regarded as constant during this first pulse and swing.

The Horizontal Pulse Force (Fp) can be regarded as constant because this is under the control of the Engineer.  We assume the ideal situation of capable of turning the Force on and off.

The Tension in the String (Fs) unfortunately, cannot be regarded as a constant.  Before the application of the Pulse Force (Fp), Fs = Fg.  When Fp is being applied, Fs MUST change.  At the new momentary stationary position, Fs must be equal and opposite to the resultant force of Fp and Fg.  Thus this particular assumption is incorrect.

[3] We cannot consider them independently if Fs is a function of Fp and Fg.  Thus this particular assumption is incorrect.

[4] As we stated, the final position for this analysis is the momentary stationary position.  There is NO velocity and hence no kinetic energy.  This particular assumption is incorrect.

[5] Fs \dot D is zero  You are making the assumption that the force vector Fs is always at right angles to the displacement vector D.  In constant circular motion such as the Earth going around the Sun, this is correct.  However, in accelerating and decelerating circular motion, this is incorrect.

[6] Thus the so called conventional analysis as outlined by you have many incorrect assumptions.

As you have rightly pointed out, without the use of Integrals, we have to make certain assumptions and simplifications.  These assumptions and simplifications may be inexact or even incorrect.  Arguing over inexact or incorrect assumptions will waste much energy and time.

I shall try to explain the Integral Assumption in the next post.  It will be edited from the notes made after the discussions at Tsing Hua University.

Lawrence Tseung
Simplified Analysis Leads Out incorrect assumptions.  It increases the Pulse rates of all involved.

[Pirate88179]

Lawrence:

It may not matter in your calculations but I believe that the figure of acceleration due to gravity of 9.8 cm2 does not apply in this case. (Pendulum)  That was calculated for a free falling body in a vaccuum.  I am not going to get into wind resistance or anything but it's the "free falling" aspect that interests me.  Since the sting is forcing the pendulum into a circular path, rather than straight, and if the pendulum is launched (started) at the 3:00 position or the 9:00 position, it would only free fall for an instant before the string causes it to begin it's circular path.  The force imposed by the string in doing this would not allow the pendulum to reach the acceleration figure for a free falling body.

The force of gravity at 1g would also not remain constant during the circular path forced by the string.  I believe it would climb and be at maximum at the 6:00 position of the pendulum arc and taper off back toward 1g, and then 0g at the extreme ends of the swing movement.

I think the most interesting thing is that at each ends of the pendulum arc, there is that one moment where, for all intents and purposes, the pendulm is weightless and would be at 0g.  Velocity would also be 0. The tension on the string would be 0.  It is this exact point in time that interests me.

I saw the slide show done by your friend. The results were not what I would have anticipated if asked beforehand.  Interesting.

Bill