Stanley Meyer replication with low input power

[RunningBare]

I'm copying this across to save me having to type it all out again.

Actually to explain, this was never a test for gas output because my tube configuration is totally inefficient anyway, this was actually a test of the bifilar transformer configuration

I'm not going to even bother completing the second test, it has already confirmed what Ravi advised and I thought about a few hours ago.

In the first test the bifilar configuration was the one Ravi suggested

In the second test which has now been running for 2 hours and barely giving much gas the original bifilar arrangement is being used
apart from the bifilar the parameters are pretty much the same, in fact I had to bring down the frequency and pulse width so that the current drawn matched the first test because it was above 0.6amps

Ok guys, I finally got some numbers you can run with...

I fed the tubes with a DC pulse at 6080hz approx.
Total current drawn by circuit and tubes 0.5amps, voltage 12.5
Then the 6080hz was gated, 90ms ON, 60ms OFF.
It took 1 hour 20 minutes to collect approx 600ml of gas.

If anyone would like to run those numbers I will be back with a second lot after another test run.

[tao]

Can you attempt to feed a frequency to your tubes based on my previous post?

the base equation, after simplification is: 717.5/L = F, where L is in meters, and F is in Hz

let google convert your inches for you: Example: http://www.google.com/search?hl=en&safe=off&q=5+in+to+m&btnG=Search

So, for 5 inch tubes, 5 in = 0.127 m ,  so F=717.5/.027 = 5,650 Hz


You might have already done this, and if you have, excuse me.......

[RunningBare]

Thanks tao, my tubes are 8cm in length, calculated frequency 8968.75 hz, I've got it very close to that now, running the test again from fresh, including a change of water.

Can you attempt to feed a frequency to your tubes based on my previous post?

the base equation, after simplification is: 717.5/L = F, where L is in meters, and F is in Hz

let google convert your inches for you: Example: http://www.google.com/search?hl=en&safe=off&q=5+in+to+m&btnG=Search

So, for 5 inch tubes, 5 in = 0.127 m ,  so F=717.5/.027 = 5,650 Hz


You might have already done this, and if you have, excuse me.......

[esaruoho]

20th september update of http://www.panaceauniversity.org/D14.pdf

[Gheller J]

Looks like d bifilar input connection has been corrected in this D14 after Ravi's schematic on d last pg.

Gh. J.